Profur aodbdb aowijwjejsjw8
Answer:
see below
Step-by-step explanation:
y' = -2e⁻ˣcos(x) -sin(x)2e⁻ˣ +e⁻ˣsin(x)-cos(x)e⁻ˣ = e⁻ˣ(-2cos(x)-2sin(x)+sin(x) -cos(x))
=e⁻ˣ(-3cos(x)-sin(x))
y'' = -e⁻ˣ(-3cos(x)-sin(x)) + (3sin(x)-cos(x))e⁻ˣ
y'' = e⁻ˣ[3cos(x)+sin(x) + 3sin(x)-cos(x)] = e⁻ˣ[2cos(x)+4sin(x)]
y''+2y'+2y = 0
e⁻ˣ[2cos(x)+4sin(x)] + 2[e⁻ˣ(-3cosx-sinx)] + 2[2e⁻ˣ cos(x)−e⁻ˣ sin(x)]
e⁻ˣ[2cos(x)+4sin(x)-6cos(x)-2sin(x)+4cos(x)-2sin(x)]
e⁻ˣ[-4cos(x)+2sin(x)+4cos(x)-2sin(x)]
e⁻ˣ[0cos(x)+0sin(x)] = 0
put but not until in cyl go into equally
19.) 14/18, 21/27
20.) 3/21, 2/14
21.) 6
22.)8/9
25.) 36/73
26.) 1/3=.33 2/8=.25 Eric is more successful
