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Colt1911 [192]
3 years ago
9

What at 25 equations that equal 36

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Equations don't equal numbers.

Sometimes their solutions, if they have one, do.

Here are three equations whose solutions are 36 :

x + 15  =  51

x/3  =  12

x² - 72x + 1,296  =  0


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Insert three arithmetic means between 4 and 10.
Bumek [7]

Answer:

5.5, 7, 8.5

Step-by-step explanation:

Find the mean of 4 and 10, that is

\frac{4+10}{2} = \frac{14}{2} = 7

Now repeat with 4 and 7 and 7 and 10

\frac{4+7}{2} = \frac{11}{2} = 5.5

\frac{7+10}{2} = \frac{17}{2} = 8.5

Hence

4, 5.5, 7, 8.5, 10 ← is an arithmetic sequence with d = 1.5

4 0
3 years ago
Please answer below!
Artist 52 [7]

Answer:

the terms are 400n , 62n 120 and 8n

the number of coefficients is 3

equa expression  is 346n+120

Step-by-step explanation:1

Combining like terms 400n400n and -62n−62n

338n+120+8n

338n+120+8n

2 Combining like terms 338n338n and 8n8n

346n+120

346n+120

For the rest of them i just counted.

8 0
3 years ago
Read 2 more answers
Two inches equal approximately how many centimeters?
Dahasolnce [82]
Two inches to centimeters is about 5.08
3 0
4 years ago
Determine whether the given differential equation is Exact or not exact. If it is exact, solve it directly. If it not exact, sol
MatroZZZ [7]

Answer:

lets take a differential equation

xy^3dx+(x^2y^2+1)dy=0\\let\\M= xy^3\\and\\N=(x^2y^2+1)

taking derivative of M w.r.t y and N w.r.t x

dM/dy=3xy^2\\dN/dx=2xy^2\\so\\dM/dy\neq dN/dx

so this is an in exact equation we will find integrating factor and make it exact equation

U=e^\int\limits^_{(-dN/dx-dM/dy)} \,/ M\\\\=e^\int\limits^ {2xy^2-3xy^2} \, /xy^3\\=e^\int\limits^ {-xy^2} /xy^3\\=e^\int\limits^{-1/y} \\=e^-^l^n^y\\=1/y

so 1/y is our integrating factor multiply it by the equation we will get an exact equation:

1/y(xy^3)dx+1/y(x^2y^2+1)dy=0\\xy^2dx+(x^2y+1/y)dy=0\\let \\M=xy^2\\and \\N=(x^2y+1/y)

take derivative

dM/dy=2xy\\dN/dx=2xy\\so\\dM/dy=dN/dx

now solving this exact equation

f(x,y)=c=\int\limits{M} \, dx +g(y)\\=\int\limits {xy^2} \, dx +g(y)\\=\frac{1}{2}x^2y^2+g(y)\\ df/dy=d/dy(\frac{1}{2} x^2y^2+g(y))=N

x^2y+g'(y)=x^2y+1/y\\g'(y)=1/y\\g(y)=lny\\f(x,y)=\frac{1}{2}x^2y^2+lny=C

7 0
3 years ago
PLZ HELP ME PLS HELP ME ​
kvasek [131]
Hows yalls day going? ❤️
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3 years ago
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