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Colt1911 [192]
3 years ago
9

What at 25 equations that equal 36

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Equations don't equal numbers.

Sometimes their solutions, if they have one, do.

Here are three equations whose solutions are 36 :

x + 15  =  51

x/3  =  12

x² - 72x + 1,296  =  0


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A gun mass of 5 kg fired a bullet of mass 10 g with the velocity of 360 km/h. What
klemol [59]

Answer:

The recoil velocity of the gun is 0.72\,\,\frac{km}{h}  and is pointing in opposite direction to the velocity of the bullet.

Step-by-step explanation:

Use conservation of linear momentum, which states that the momentum of the bullet (product of the bullet's mass times its speed) should equal in absolute value the momentum of the recoiling gun (its mass times its recoil velocity).

We also write the mass of the bullet in the same units as the mass of the gun (for example kilograms). Mass of the bullet = 0.010 kg

In mathematical terms, we have:

5\, kg * v= 0.01 \,kg\,* 360\,\frac{km}{h} \\v=\frac{0.01\,*360}{5} \,\,\frac{km}{h}\\v=0.72\,\,\frac{km}{h}

6 0
3 years ago
Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by
Fudgin [204]

The given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

Given that, the expression can be written as.

(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)

By simplifying the above equation,

\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}

By taking out the common terms from the equation,

\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}

By simplifying the above equation by cancel out the common factors.

\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}

Now, by taking (-1) common from (-2c+1) we get,

\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}

By simplifying the above equation, we get the expression,

-3c

So the given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

7 0
2 years ago
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