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3 years ago

Bill ate 2/3 of a pizza. Sam ate 1/3 of what was left. What part of the whole pizza did Sam eat?

Mathematics

2 answers:

Semenov [28]3 years ago

5 0

Answer:

0.3333333333333333....

puteri [66]3 years ago

4 0

1/3 of the pizza is left. 1/3 of the 1/3 was eaten

1/3 × 1/3 = 1/9

same ate 1/9 of the pizza

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What is greater 1/3 or 1/8

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1/3 is greater. Picture a pie with nothing cut into it. Then, you cut 3 equal pieces out of it, leaving no pie remaining. So, if you take 1 piece, you have 2 pieces that you didn't take. So if you do the exact same thing, but you cut <em>8 </em>pieces out of the pie and you take 1 piece, there are still 7 pieces remaining. So 1/8 is a smaller part of the pie than the 1/3, since you are cutting the pie into 8 identical pieces while with 1/3 you are cutting the same sized pie into 3 pieces. Sorry if I was confusing, just ask me if you want an easier-to-understand explanation. Also, if you pick a "brainliest" answer, it actually <em>gives </em>you points.

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3 years ago

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Solve by substitution ANSWER NOW

Maslowich

Y = -5x + 9
y = 5x + 7

5x + 7 = -5x + 9
5x + 5x = 9 - 7
10x = 2
x = 2/10 reduces to 1/5

y = 5x + 7
y = 5(1/5) + 7
y = 1 + 7
y = 8

solution is (1/5,8)

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3 years ago

Please help thank you!

oksano4ka [1.4K]

Answer:

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3 years ago

A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa

g100num [7]

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

$8 \times h + 5 \times f = 24$

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

$6 \times h + 2 \times f = 16.60$

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

5 0

3 years ago