The probability of the offspring of a heterozygous father and homzygous mother having five fingers is 50%.
<h3>How to calculate genotype of a cross?</h3>
According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.
If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:
This shows that the probability of the offspring of a heterozygous father and homzygous mother having five fingers is ½ (50%).
Learn more about genotype at: brainly.com/question/12116830
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at what stage of human development wuold you exept to first see abeating heart? <u>the</u><u> </u><u>answ</u><u>er</u><u> is</u><u> </u><u>ç</u>
Answer:
Sure grass. And there is a lot of grass. Compete with wild horses, wild pigs, wild goats, wild "golfer's who are way off the fairway. Wild deer are in the forests, wild goats in the hills so buffalo and horses manage the plains and the back nine. So much grass there was no competition...with the wild rabbits. Grass continues to grow. The buffalo move to greener pastures once they mowed down the other fields. When there were Millions of them, they were not starving.
Explanation: Got this from somewhere hoping it helps!
Answer:
The frequency of the dominant (normal) allele in the population (p) is simply 1 - 0.02 = 0.98 (or 98%). The percentage of heterozygous individuals (carriers) in the population.
Explanation:
(i found it here if you have questions
Hardy-Weinberg - Kansas State Universitywww.k-state.edu › parasitology › biology198 › answers1)
