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natali 33 [55]
3 years ago
10

In a population with two alleles, B and b, the allele frequency of b is 0.4. B is dominant to b. What is the frequency of indivi

duals with the dominant phenotype if the population is in Hardy-Weinberg equilibrium
Biology
2 answers:
Nady [450]3 years ago
6 0

Answer:

The frequency of the number of individuals with the dominant phenotype is 0.84

Explanation:

in Hardy-Weinberg equilibrium equation, <em>p</em> & <em>q</em> are used to represent the frequency of alleles in a population.

Frequency = Total No of 1 allele / total alleles

if frequency of <em>p</em> allele = 0.6

therefore <em>p</em> + <em>q</em> = 1        ==> <em>q</em> = 0.4

To get these frequencies, square (p + q)

<em>p</em>² + 2<em>pq</em> + <em>q</em>² = 1

The proportion of individuals that are homozygous dominant for B allele is p²

<em>P</em>² = 0.6 x 0.6 = 0.36

The proportion of individuals that are heterozygous for B and b alleles is 2<em>pq</em>

2<em>pq</em> = 2 x 0.6 x 0.4 = 0.48

The frequency of number of individuals with dominant female type

= 0.36 + 0.48 = 0.84

Yuki888 [10]3 years ago
4 0

Answer:

The frequency of the dominant (normal) allele in the population (p) is simply 1 - 0.02 = 0.98 (or 98%). The percentage of heterozygous individuals (carriers) in the population.

Explanation:

(i found it here if you have questions

Hardy-Weinberg - Kansas State Universitywww.k-state.edu › parasitology › biology198 › answers1)

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