Answer:
The frequency of the number of individuals with the dominant phenotype is 0.84
Explanation:
in Hardy-Weinberg equilibrium equation, <em>p</em> & <em>q</em> are used to represent the frequency of alleles in a population.
Frequency = Total No of 1 allele / total alleles
if frequency of <em>p</em> allele = 0.6
therefore <em>p</em> + <em>q</em> = 1 ==> <em>q</em> = 0.4
To get these frequencies, square (p + q)
<em>p</em>² + 2<em>pq</em> + <em>q</em>² = 1
The proportion of individuals that are homozygous dominant for B allele is p²
<em>P</em>² = 0.6 x 0.6 = 0.36
The proportion of individuals that are heterozygous for B and b alleles is 2<em>pq</em>
2<em>pq</em> = 2 x 0.6 x 0.4 = 0.48
The frequency of number of individuals with dominant female type
= 0.36 + 0.48 = 0.84
