X=rcos(t), y=rsin(t). so y/sin(t) = r => csc(t) = r/y. so for now we have r*(r/y)=8. To solve for r, do x^2 + y^2 = r^2, so r=sqrt(x^2 + y^2). So we have sqrt(x^2 + y^2<span>)*(sqrt(x^2 + y^2<span>)/y</span>)=8, or (x^2+y^2)/y = 8, or x^2/y + y = 8.</span>
we know that
<u>Unit Rate</u> is the ratio of two measurements in which the second term is ![1](https://tex.z-dn.net/?f=1)
we have
![2\frac{1}{2}\ liters=\frac{2*2+1}{2}=\frac{5}{2}\ liters](https://tex.z-dn.net/?f=2%5Cfrac%7B1%7D%7B2%7D%5C%20liters%3D%5Cfrac%7B2%2A2%2B1%7D%7B2%7D%3D%5Cfrac%7B5%7D%7B2%7D%5C%20liters)
so
Corey bought
of paint for ![\$60](https://tex.z-dn.net/?f=%5C%2460)
by proportion
<u>Find the cost of one liter of paint</u>
![\frac{60}{(5/2)}\frac{\$}{liters}=\frac{x}{1}\frac{\$}{liters} \\ \\x*\frac{5}{2}=60\\ \\ x=2*60/5\\ \\x=\$24](https://tex.z-dn.net/?f=%5Cfrac%7B60%7D%7B%285%2F2%29%7D%5Cfrac%7B%5C%24%7D%7Bliters%7D%3D%5Cfrac%7Bx%7D%7B1%7D%5Cfrac%7B%5C%24%7D%7Bliters%7D%20%5C%5C%20%5C%5Cx%2A%5Cfrac%7B5%7D%7B2%7D%3D60%5C%5C%20%5C%5C%20x%3D2%2A60%2F5%5C%5C%20%5C%5Cx%3D%5C%2424)
therefore
<u>the answer is</u>
the cost per liter of the paint is equal to ![24\frac{\$}{liter}](https://tex.z-dn.net/?f=24%5Cfrac%7B%5C%24%7D%7Bliter%7D)
Answer:
y = Five-sixths x – 12
Step-by-step explanation:
In the picture attached, the given line is shown. Its slope is:
m = [6 - (-4)]/[12 - 0] = 5/6
The line that is parallel to the given line has the same slope.
A line with slope m that pass through (x1, y1) satisfies:
y - y1 = m(x - x1)
Replacing with m = 5/6 and point (12, -2):
y - (-2) = 5/6(x - 12)
y + 2 = 5/6x - 10
y = 5/6x - 10 - 2
y = 5/6x - 12
Answer:
12-foot shadow
Step-by-step explanation:
hope this helps :3
if it did pls mark brainliest
sorry if im wrong
Answer:
- x = 31 - 2y - 3z
- y = (31 - x - 3z)/2
- z = (31 -x -2y)/3
Step-by-step explanation:
Subtract the terms not containing the variable of interest, then divide by the coefficient of the variable.
x = 31 -2y -3z . . . . . the coefficient of x is 1, so we're done
__
2y = 31 -x -3z
y = (31 -x -3z)/2
__
3z = 31 -x -2y
z = (31 -x -2y)/3