Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3
Note: Negative time (-0.2) is not valid
There are 40 cats in the ecosystem.
You set 1/5 equal to x/200. Then you cross multiply the fractions to get 5x=200. You divide both terms by 5 to get x, which equals 40.
The set of all possible events Ω
Ω = 24 ( 4*7 = 28 stick)
<span>set of events favorable A
A = 7 ( </span><span>sticks of green is 7)
</span><span>Probability P
P(A) = A/</span>Ω = 7/28 = 1/4 = 0,25
Answer A
<span>The first person has the ability to draw seven green sticks of twenty-four </span>
Answer:
A) 
B) 
Step-by-step explanation:
A survey of 46 college athletes found that
- 24 played volleyball,
- 22 played basketball.
A) If we pick one athlete survey participant at random, the probability they play basketball is
B) If we pick 2 athletes at random (without replacement),
- the probability we get one volleyball player is
- the probability we get another basketball player is
(only 45 athletes left).
Thus, the probability we get one volleyball player and one basketball player is
Answer:
no
Step-by-step explanation:
Let f represent the fraction of C-14 remaining as a function of the time t in years. Since the half-life of C-14 is about 5570 years, we have ...
f = (1/2)^(t/5570)
Taking the log and solving for t, we get ...
log(f) = (t/5570)log(1/2)
5570·log(f)/log(1/2) = t
Filling in the given value for f, the value of t we get is ...
5570·log(0.65)/log(0.5) = t ≈ 3462
It appears the estimate of 4000 years is a bit high.
