Answer:
mystr = input("Enter a string ")
length = len(mystr)
while length<10:
mystr = input("Enter a string ")
length = len(mystr)
if(length>=10):
break
if len(mystr)%2==0:
print(mystr.lower())
else:
print(mystr.upper())
Explanation:
The variable mystr is used to save user's input which is received with the input function
A second variable length is used to save the length of the input string Using a while statement the user is continually prompted to enter a string while length is less than 10.
If length is greater or equal to 10. We check for even or odd using the modulo (%) operator.
We use lower() and upper() to change the case of the string
To start combining, select the Merge Mode option on the Comparison tab. Next, click the button next to the line you wish to merge in order to replace content from the right pane with content from the left pane.
<h3>How is boundary layer thickness calculated?</h3>
- Where x is a position parallel to the wall, y is a coordinate normal to the wall, v is a (small) viscosity, u = (u, v) is the velocity, is the vorticity, and so on. The boundary conditions are as follows: u(x,y = +,t) = U, and u(x,y = 0,t) = 0.
- To gauge the overall pressure, a vertically sliding Pitot tube is employed. So that the growth of the boundary layer in the flow direction can be seen, the total pressures can be recorded at various distances from the plate surface. Static pressure is gauged at a different measurement location.
- To start combining, select the Merge Mode option on the Comparison tab. Next, click the button next to the line you wish to merge in order to replace content from the right pane with content from the left pane. Alternatively, you can pick a discrepancy and choose Replace Content from the Comparison tab.
To learn more about Boundary conditions refer to:
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Answer: Hello your question is poorly written attached below is the well written question
answer:
a) Determine ( compute ) the difference between the max and minimum value. determine the Min and max values using 1.5n comparisons
time efficiency = θ( n )
b) A(n-1) - A(0)
time efficiency = θ( 1 )
Explanation:
a) An unsorted array
To find the maximum and minimum values scan the array of elements , then determine ( compute ) the difference between the max and minimum value. to determine the range. Alternatively determine the Min and max values using 1.5n comparisons
Algorithm's time efficiency = θ( n )
b) A sorted array
To determine the range, we will determine the difference between the first and last element i.e. A(n-1) - A(0)
time efficiency = θ( 1 )
Answer:
There are certainly many hidden costs, and you need to find them out. I am listing some. The GPU can cost a lot if you are using them for complex computing like in the case of Bitcoin. You need to pay heavy electricity bills as well. And if you want to install the webserver then as well, you need to keep your computer open all the time, and pay a good sum as an electricity bill. Many more hidden costs can be found. And one out of above is used in Schools, the webserver. Some more hidden costs can be Network cost, as the school is big, and you need to connect all through LAN, and at times we also need WAN set up. And these are another hidden cost. Various education licenses come for free, and smart classes cost as well. The video conferencing, VOIP, etc costs as well. Smart classes training by various computer training institute for teachers like one from adhesive.
Explanation:
Please check the answer section.