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Olenka [21]
3 years ago
9

In a registration database, Ross has tables for student, professor, classroom, class, class-hour. Since his campus has about 12,

000 students, when he runs queries about what student is in what class, taught by what professor in what classroom at which hour, the DBMS software will have to perform many _________
a)Axes
b)Parallels
c)Concretes
d)Joins
e)Enrolls
Computers and Technology
1 answer:
Zina [86]3 years ago
7 0

Answer:

The correct answer for the given question is option(d) i.e " joins ".

Explanation:

Joins are used in the database to combining the two or more than two tables.The data base management system (DBMS) performing the joining queries to combine the student, professor, classroom, class, class-hour tables.The join connected the two or more table by matching the columns between the tables .

Their are many types of joining in the database.

1.  Inner join.

2. Outer join .

3. Left join.

4. Natural join.

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Tyra used the software development life cycle to create a new game. After debugging and documenting code, she released it to her
REY [17]

Answer:

Maintenance

Explanation:

Maintenance

This primarily involves updating and making improvements based on user feedback, as well as resolving any defects that arise.

6 0
3 years ago
How does Mixed Reality expand on Augmented Reality?
taurus [48]

Mixed Reality expand on Augmented Reality option d: by enabling real-time interaction between real and virtual objects.

<h3>How does mixed reality expand on augmented reality?</h3>

Mixed reality is known to be one that is made up of both augmented reality and that of augmented virtuality.

Note that Mixed reality is one that acts so as to make an environment with interactive kinds of digital objects. Augmented reality needs a screen to be able to experience the augmented experience. Mixed reality is said to be experienced via the a headset.

Hence, Mixed Reality expand on Augmented Reality option d: by enabling real-time interaction between real and virtual objects.

Learn more about Augmented Reality from

brainly.com/question/9054673

#SPJ1

3 0
2 years ago
Ethernet ensures that _____ on a shared network never interfere with each other and become unreadable.
Dmitry [639]

Answer:

Signals.

Explanation:

Encryption is a form of cryptography and typically involves the process of converting or encoding informations in plaintext into a code, known as a ciphertext. Once, an information or data has been encrypted it can only be accessed and deciphered by an authorized user.

Some examples of encryption algorithms are 3DES, AES, RC4, RC5, and RSA.

Ethernet ensures that signals on a shared network never interfere with each other and become unreadable through the use of encapsulation and standard encryption protocols.

In Computer Networking, encapsulation can be defined as the process of adding a header to a data unit received by a lower layer protocol from a higher layer protocol during data transmission. This ultimately implies that, the header (segment) of a higher layer protocol such as an application layer, is the data of a lower layer such as a transportation layer in the Transmission Control Protocol and Internet Protocol (TCP/IP).

The TCP/IP model comprises of four (4) layers;

1. Application layer: this is the fourth layer of the TCP/IP model. Here, the data unit is encapsulated into segments and sent to the transport layer.

2. Transport layer (layer 3): it receives the segment and encapsulates it into packets and sends to the internet layer.

3. Internet layer (layer 2): packets are encapsulated into frames.

4. Network layer (layer 1): frames are then converted into bits and sent across the network (LAN).

Hence, the data unit encapsulated inside a packet is known as segment, which is typically referred to as packet segmentation.

Additionally, these data, segments, packets, frames and bits transmitted across various layers are known as protocol data units (PDUs).

8 0
3 years ago
1. Scrieţi un program care citeşte un număr natural n şi determină produsul cifrelor impare ale lui n. De exemplu, pentru n = 23
saveliy_v [14]

Answer:

1.  

num1 = input("Enter the value of n")  

n = int(num1)  

def calc(n):  

Lst = []  

while n > 0:  

remainder = n % 10  

Lst.append(remainder)  

quotient = int(n / 10)  

n = quotient  

i = len(Lst) - 1  

sum = 1  

for i in range(0, len(Lst)):  

if(i % 2 != 0):  

sum *=Lst[i];  

else:  

continue  

print(sum)  

return(0)  

\ r2

num=input("Enter the value of n")

arr=[12,-12,13,15,-34,-35,35,42]

def div7positive():

  sum = 0

  m = 0

  i = 0

  while m <= 7:

      if(arr[i]>=0 and arr[i]%7 == 0):

          sum +=arr[i]

      i = i + 1

      m += 1

       

   

  print("sum of number divisible by 7 and positive is", +sum);

div7positive()

\ r

\ r3.Write an algorithm that reads a natural number n and calculates the sum:

\ rS = 1 / (1 * 2) + 1 / (2 * 3) + 1 / (3 * 4) +… + 1 / ((n-1) * n)

\ r

num=input("Enter the value of n")

def sumseries():

  sum = 0

  m= 0

  while m <= 7:

      sum +=1/((int(num)-1)*int(num))

      m += 1

  print("sum of series is", +sum)

sumseries()

\ R4. Read a natural number n. Calculate the sum of its own divisors n. For example, for n = 12, the sum of its own divisors is 2 + 3 + 4 + 6 = 15

num=input("Enter the value of n")

def sumdivisors():

  sum = 0

  m= 2

  while m <= int(num):

      if int(num) % m == 0:

          sum += m

      m += 1

  print("sum of divisors is", +sum)

sumdivisors()\ r

\ R5. We read a natural number n and then whole numbers. Calculate and display the sum of the natural numbers between 10 and 100. For example, if n = 5 and then read 30, –2, 14, 200, 122, then the sum will be 44 (that is, 30 + 14).

\ r

Lst = []  

num=input("Enter the value of n")

i = 0

while i<= int(num):

  num1=input("Enter the element of array")

  Lst.append(int(num1));

  i += 1

def numbet0and100():

  sum = 0

  m= 0

  while m <= int(num):

      if Lst[m] <= 100 or Lst[m] >=0:

          sum += Lst[m]

      m += 1

  print("sum of numbers between 0 and 100 is", +sum)

numbet0and100()

\ R6. A natural number n of maximum 4 digits is read. How many digits are in all numbers from 1 to n? For example, for n = 14 there are 19 digits, and for n = 9 there are 9 digits.

\ r

num = input("Enter the value of n")

n = int(num)

print(“sum as required is:” (n -9) + n)  

 

\ R7. Read the natural numbers n and S, where n can be 2, 3, 4 or 5. Show all the numbers of n digits that have the numbers in strictly ascending order, and the sum of the digits is S. For example, for n = 2 and S = 10, 19, 28, 37, 46 will be displayed.

num = input("Enter the value of n")

n = int(num)

Lst = []

def calc(n):

  i = 1

  total = pow(10,n)

  while i <= total:

      j = i

      while j > 0:

          remainder = j % 10  

          Lst.append(remainder)

          quotient = int(j / 10)

          if quotient > 0:

              j = quotient

          else:

              length = len(Lst) - 1

              sum = 0

              while length >= 0:

                  sum += Lst[length]

                  length = length - 1

              if sum == pow(10,n):

                  print(j)

              k = len(Lst)

              del Lst[0:k]

      i = i + 1

  return(0)

calc(n)

\ r

\ R8. We consider the row 1, 1, 2, 3, 5, 8, 13, ... in which the first two terms are 1, and any other term is obtained from the sum of the preceding two. Write an algorithm that reads a natural number n and displays the first n terms of this string. For example, for n = 6, 1, 1, 2, 3, 5, 8 will be displayed.

\ r

nterm = int(input("What number of terms do you want?"))

a, b = 0, 1

totalcount = 0

if nterm <= 0:

 print("Please input a positive number")

elif nterm == 1:

 print("Fibonacci number upto which",nterm,":")

 print(a)

else:

 print("Fibonacci series:")

 print(nterm)

 while totalcount < nterm:

     print(a)

     nth = a + b

     a = b

     b = nth

     totalcount += 1

 

\ 9. Write an algorithm that reads two natural numbers n1 and n2 and displays the message "yes" if the sum of the squares of the digits of n1 is equal to the sum of the numbers of n2 or "no" otherwise. For example, for n1 = 232 and n2 = 881, "yes" will be displayed, and for n1 = 45 and n2 = 12, "no" will be displayed.

num1 = input("Enter the value of n")

num3 = input("Enter the value of n")

n = int(num1)

num2 = int(num3)

def calc(n):

  Lst = []

  while n > 0:

      remainder = n % 10  

      Lst.append(remainder)

      quotient = int(n / 10)

      n = quotient

       

  i = len(Lst) - 1

  sum = 0

  while i >= 0:

      sum += Lst[i]* Lst[i]

      i = i - 1

  return(sum)

def calc1(num2):

  Lst = []

  while num2 > 0:

      remainder = num2 % 10  

      Lst.append(remainder)

      quotient = int(num2 / 10)

      num2 = quotient

       

  i = len(Lst) - 1

  sum = 0

  while i >= 0:

      sum = Lst[i] + Lst[i]

      i = i - 1

  return(sum)

a = calc(n)

b = calc1(num2)

if a == b:

  print("yes")

else:

  print("No")

\ r

\ R10. Write an algorithm that reads a natural number n and displays the message "yes" if all of its n numbers are distinct, or "no" if n does not have all the distinct digits. For example, for n = 37645 it will display "yes" and for 23414 it will show "no".

\ r

num1 = input("Enter the value of n")

n = int(num1)

def calc(n):

  Lst = []

  while n > 0:

      remainder = n % 10  

      Lst.append(remainder)

      print( remainder)

      quotient = int(n / 10)

      n = quotient

       

  flag = 1

  for i in range(0, len(Lst)):

      for j in range(i+1, len(Lst)):    

          if Lst[i] == Lst[j]:    

              flag = 0

              break

           

  if flag == 1:

      print("YES")

  else:

      print("NO")

  return(0)

Explanation:

Please check answer.  

3 0
3 years ago
What is a hacker who breaks into other people's computer systems and may just look around or steal and destroy?
inessss [21]
A cyber gang or cyber theif
5 0
3 years ago
Read 2 more answers
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