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sukhopar [10]
2 years ago
8

PLSS HELPP PLS HURRYY!!

Mathematics
1 answer:
lukranit [14]2 years ago
8 0

Answer: THE ANSWER IS THE LAST CHECK BOX.

Step-by-step explanation:

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What is the square root of 149 rounded to the nearest tenth?
Ad libitum [116K]
Rounded to the nearest tenth, the square root of 149 is 12.2.
3 0
3 years ago
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Translation: 6 units right and 3 units down<br> s(-3, 3), C(-1, 4), W(-2,-1)
sdas [7]
S (3, 0)
C (5, 1)
W (4, -4)

Explanation
You take the first number and add 6 to it and you get the new number and then you take the second number and subtract 3 from it

S: -3 + 6 = 3
S- 3 - 3 = 0

C: -1 + 6 = 5
C: 4 - 3 = 1

W: -2 + 6 = 4
W: -1 - 3 = -4
3 0
2 years ago
5                 3                4               7          26       30
Furkat [3]
Please explain more to the question where do the numbers go
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3 years ago
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You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us
Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that    

step 1

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

r=10\%=10/100=0.10\\n=4  

substitute in the formula above

A=P(1+\frac{0.10}{4})^{4t}  

A=P(1.025)^{4t}  

Applying property of exponents

A=P[(1.025)^{4}]^{t}  

A=P(1.1038)^{t}  

step 2

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

r=10\%=10/100=0.10  

substitute in the formula above

A=P(e)^{0.10t}  

Applying property of exponents

A=P[(e)^{0.10}]^{t}  

A=P(1.1052)^{t}  

step 3

Compare the final amount

P(1.1052)^{t} > P(1.1038)^{t}

therefore

Find the difference

P(1.1052)^{t} - P(1.1038)^{t} ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0
3 years ago
Why...WHY..............
mars1129 [50]

Answer:

because I said so....that's why

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2 years ago
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