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3 years ago

Help out please thank you

Mathematics

2 answers:

Verizon [17]3 years ago

7 0

Answer: 6a. 3 1/3, 6b. 2 2/5, 6c. 1/4, 6d. 9/10

Step-by-step explanation: You can use math/way or Soc/ratic to find the answers. Math/way is a website, Socr/atic is an app.

MrMuchimi3 years ago

4 0

Do KCF ( keep change flip ) 5/6 divided by 1/4 keep the 5/6 change the division sign to a multiplication sign and change 1/4 to 4/1 and multiply across meaning 5x4 =20 and 6x1=6 =20/6 if you simplify it it will get you 10/3 because the the simplified number for 20/6 is 2 ,2x10 is 20 and 2x3 is 6 and just do ( KCF ) for all 3 hope it helped !

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8th grade math

UkoKoshka [18]

Answer:

10 Milk chocolates

8 dark chocolates

6 white chocolates

24 TOTAL

\frac{10}{24} Probability that Hanissa choose a milk chocolate

Now, since she has already eaten one chocolate, then what's left is 23 chocolates.

So, since the second one should be a white chocolate and there are 6 of them, then

\frac{6}{23} - probability of choosing a white chocolate.

Then, multiply,

( \frac{10}{24} )( \frac{6}{23} )= \frac{60}{552} or \frac{5}{46}

Answer: 5/46 or 10.87%

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

HELP PLEASE

Nikolay [14]

Answer:

The 1st the 3rd and 4th are the answers

Step-by-step explanation:

Edgen

4 0

2 years ago

For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r < d. n = −67, d = 8

Firlakuza [10]

Answer:

$q = 8$

$r = 3$

Step-by-step explanation:

Given

$n = dq + r$

$0 \le r < d$

$n = 67$ --- not -67

$d = 8$

Required

Find q and r

Substitute values for d and b

$n = dq + r$

$67 = 8 * q + r$

$67 = 8q + r$

Make q the subject

$q = \frac{67 - r}{8}$

$0 \le r < d$ means that r is less than 8 but greater than or equal to 0

And r and q are integers.

Let $r = 3$

$q = \frac{67 - 3}{8}$

$q = \frac{64}{8}$

$q = 8$

No other true values of r and q can be gotten.

7 0

2 years ago

Find the average rate of change for the given function from x = −1 to x = 2.

GREYUIT [131]

Well, if you look at the graph, when x = -1, y or f(x) = 4.

and when x = 2, y = 0.

$\bf slope = m = \cfrac{rise}{run} \implies 
\cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby 
\begin{array}{llll}
average~rate\\
of~change
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
x_1=-1\\
x_2=2
\end{cases}\implies \cfrac{f(2)-f(-1)}{2-(-1)}\implies \cfrac{0-4}{2+1}\implies \cfrac{-4}{3}$

8 0

2 years ago