Answer:
10 Milk chocolates
8 dark chocolates
6 white chocolates
24 TOTAL
\frac{10}{24} Probability that Hanissa choose a milk chocolate
Now, since she has already eaten one chocolate, then what's left is 23 chocolates.
So, since the second one should be a white chocolate and there are 6 of them, then
\frac{6}{23} - probability of choosing a white chocolate.
Then, multiply,
( \frac{10}{24} )( \frac{6}{23} )= \frac{60}{552} or \frac{5}{46}
Answer: 5/46 or 10.87%
Step-by-step explanation:
Answer:
The 1st the 3rd and 4th are the answers
Step-by-step explanation:
Edgen
Answer:


Step-by-step explanation:
Given


--- not -67

Required
Find q and r
Substitute values for d and b



Make q the subject

means that r is less than 8 but greater than or equal to 0
And r and q are integers.
Let 



No other true values of r and q can be gotten.
Well, if you look at the graph, when x = -1, y or f(x) = 4.
and when x = 2, y = 0.