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Sergeeva-Olga [200]
3 years ago
6

Scatterplot A correlation coefficient

Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Well I sent you sum pictures

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Which scenario best matches the inequality x > 3? A. Joanna needs to be in bed by 10 p.M. It's now just past 7 p.M. How many
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C

Step-by-step explanation:

If Ricardo started studying at 4 p.m and for sure will not stop until after 7 p.m, that means that he will be studying for 3 hours at least, and maybe even longer. So the time he will spend studying is at least 3 hours.

Therefore, x>3, where x is the time Ricardo will spend studying.

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Ede4ka [16]
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The above statement is false because for intentionally writing a check on an account with sufficient funds, it is only considered illegal when it is intended for check kiting, it is written above $100 and has been done more than once.

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I think i found the right one but I let her go thru my things but she wont lemme go thru her stuff what does that mean :( I want
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Step-by-step explanation:

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3 years ago
A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0
3 years ago
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