The new pool is 18.84 feet larger in circumference than the old one.
<u>Explanation:</u>
Given:
Circumference of the pool = 47.1 feet
Diameter of the new pool, d = 21 feet
radius, r = 21/2 feet
Circumference of the new pool = ?
We know:
Circumference = 2πr
where,
r is the radius
On substituting the value:
C = ![2 X 3.14 X \frac{21}{2}](https://tex.z-dn.net/?f=2%20X%203.14%20X%20%5Cfrac%7B21%7D%7B2%7D)
C = 65.94 feet
The difference in circumference of the two pools = 65.94 - 47.1 feet
= 18.84 feet
Therefore, the new pool is 18.84 feet larger in circumference than the old one.
65.25 - 40.50 = How much longer the pool is than wide
= 24.75 longer
It is also or about 38%.
Your answer will be D 0.60
A dollar is 1.00 so 0.60 will be 3/5
Answer: 2.4 miles per hour
Step-by-step explanation: just do 7.2/3=2.4
or another way you could do this is do 2.4 x 3=7.2
A point (-0.8, 0.6) will be a point on the unit circle in the second quadrant. Since it is a unit circle, its radius is 1, and we have
sin(α) = y = 0.6
cos(α) = x = -0.8
tan(α) = y/x = 0.6/-0.8 = -0.75
The angle is α = arccos(-0.8) ≈ 143.13°
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For the unit circle, the trig values are always the coordinates or their ratio as shown above, regardless of quadrant.