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Afina-wow [57]
3 years ago
5

Hy plzz help me friends​

Computers and Technology
2 answers:
tamaranim1 [39]3 years ago
7 0

Answer:

Ram which stands for random access memory, and Rom which stands for read only memory are both present in your computer. Ram is volatile memory that temporarily stores the files you are working on. Rom is non-volatile memory that permanently stores instructions for your computer

timama [110]3 years ago
3 0

Answer:

Ok so RAM is Random-Access-Memory.

RAM can store data just like in a hard drive - hdd or solid state drive - ssd

but the thing is that ram is really fast and data is only stored when RAM chips get power. On power loss your all data will be lost too.

ROM thanslates to Read-Only-Memory - so data in ROM chips can't be modifyed computer can just read the data but not write.

Read-only memory is useful for storing software that is rarely changed during the life of the system, also known as firmware.

Have a great day.

Explanation:

You might be interested in
Program code that can be evaluated to a value is called a(n):__________
stira [4]

Answer:

The answer is "expression"

Explanation:

An expression is a term or phrase, which is commonly used to transmits certain concepts, perceptions as thoughts. It is a mixed form of more than one operands, which is used to determines the values. It is a legal symbol, that combines the representing word like, operators, constants, and variables, that is arranged by language law.  

please find the attachment for example.

8 0
3 years ago
The _____ is the button that you push to take a photograph. i think its B Help PLZ
Sati [7]

Answer:

C

Explanation:

see the image on this web site as example: https://www.digitaltrends.com/photography/what-does-this-do-an-explanation-of-dslr-buttons/

4 0
4 years ago
PYTHON
Nina [5.8K]

Answer:

This is one of the efficient ways to find the number of occurrences of a given number in a list:

<h3><u>def find_num(arr,n):</u></h3><h3><u>    return len([count for count in arr if count == n])</u></h3><h3><u>print(find_num([0,1,1,1,0],1))</u></h3>

If you want a simpler version, you can try this:

<h2><u>def find_num(arr,n):</u></h2><h2><u>    count = 0 </u></h2><h2><u>    for i in range(len(arr)): </u></h2><h2><u>        if arr[i]==n: </u></h2><h2><u>            count += 1 </u></h2><h2><u>    return count</u></h2><h2><u>print(find_num([0,1,1,1,0],1))</u></h2>

This is the simplest method:

<h2><u>arr = [0,1,1,1,0]</u></h2><h2><u>print(arr.count(1))</u></h2>

I think I gave you enough examples. This should get you started off easily.

If you need an explanation, I am happy to help you. BTW I started python 6 months back so even I am pretty new to this.

4 0
3 years ago
Write a static method named evenNumbers that accepts a string of text as a parameter. Assume that the text is a series of intege
Allisa [31]

Answer:

// Program is written in Java Programming Language

// Comments are used for explanatory purpose

// Import input/output and utility libraries

import java.io.*;

import java.util.*;

Declare class/

public class Numbers {

// Main method goes here

public static void main(String[] args) throws FileNotFoundException

{

// Read input from text file evenFile.txt; Assume file name is evenFile.txt

Scanner input = new Scanner(new File("evenFile.txt"));

// Call static method here

evenNumbers(input);

}

// Static method evenNumbers begins here

public static void evenNumbers(Scanner input)

{

// Declare and initialise Variables

String Nums = input.nextLine(); // Read all number in txt file

Scanner numbers = new Scanner (Nums);

int count = 0; // Number count

int evens = 0; // Even count

int sum = 0; // Summation of numbers

// Check if number is integer. If yes, continue the below operations

while (numbers.hasNextInt())

{

int num = numbers.nextInt();

count++;

sum = sum + num;

if(num % 2 == 0) // check for even

{

evens++;

}

}

System.out.println("Total numbers= " + count); // Print total number

System.out.println("Sum of numbers = " + sum); // Print summation of numbers

System.out.println("Total evens = " + evens); // Print total even

//Calculate and print percentage of even number

double percent = ((double)evens/count)*100.0);

System.out.println("Percent of even number = " +percent);

}

}

// End of program

8 0
3 years ago
Read 2 more answers
Plzz help.... <br><br>i will mark u as brainliest if u answer correct
shtirl [24]

Answer:

import java.util.Scanner;

class Main {

 public static void main(String[] args) {

   Scanner scan = new Scanner(System.in);

   while(true) {

     System.out.print("Enter an integer (0 to exit): ");

     int num = scan.nextInt();

     if (num == 0) break;

     if (num%3 == 0 && num%5 == 0) {

       System.out.printf("%d is divisable by both 3 and 5.\n", num);

     }

     else if (num%3 == 0 && num%5 != 0) {

       System.out.printf("%d is divisable by 3 but not by 5.\n", num);

     }

     else if (num%3 != 0 && num%5 == 0) {

       System.out.printf("%d is divisable by 5 but not by 3.\n", num);

     } else {

       System.out.printf("%d is not divisable by 3 or 5.\n", num);

     }

   }

   scan.close();

 }

}

3 0
3 years ago
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