Answer:
Step-by-step explanation:
We can solve the problem in this way:
- The 1st information that we have is that the four numbers are even and consecutive integer. Let's call these numbers A, B, C and D. This means that:
(since the distance between two even consecutive numbers is 2)
- The 2nd information that is given is that the sum of the first and third multiplied by 3 equals 28 less than 5 times the fourth, so:
(1)
Now we rewrite eq(1) by using:
and
(obtained by combining the 3 first equations)
So we get:
Solving this equation for C,
So the other numbers are: