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3 years ago

Y=-4/5x+7 in general form Please answer quickly! ;)

Mathematics

1 answer:

USPshnik [31]3 years ago

8 0

Answer:

In order to graph y=%284%2F5%29%2Ax-7 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=0

y=%284%2F5%29%2A%280%29-7

y=0%2F5-7 Multiply

y=-35%2F5 Add

y=-7 Reduce

So here's one point (0,-7)

Now lets find another point

Plug in x=5

y=%284%2F5%29%2A%285%29-7

y=20%2F5-7 Multiply

y=-15%2F5 Add

y=-3 Reduce

So here's another point (5,-3). Add this to our graph

Now draw a line through these points

So this is the graph of y=%284%2F5%29%2Ax-7 through the points (0,-7) and (5,-3)

So from the graph we can see that the slope is 4%2F5 (which tells us that in order to go from point to point we have to start at one point and go up 4 units and to the right 5 units to get to the next point) the y-intercept is (0,-7)and the x-intercept is (8.75,0) ,or (35%2F4,0)

We could graph this equation another way. Since b=-7 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,-7).

So we have one point (0,-7)

Step-by-step explanation:

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3 years ago

What is the slope of a line that contains the points (12,17) and (-8,-17)

professor190 [17]

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$1 \frac{7}{10} \: or \: 1.7$
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4 years ago

A dolphin can swim up to 40 miles per hour.what is the speed in feet per hour?

zalisa [80]

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3 years ago

According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x^5

nata0808 [166]

Answer:

The correct option is A.

Step-by-step explanation:

The question is:

According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 – 2x4 + 9x3 – x2 + 12?

A).f(x) = 3x5 – 2x4 – 9x3 + x2 – 12

B).f(x) = 3x6 – 2x5 + 9x4 – x3 + 12x

C).f(x) = 12x5 – 2x4 + 9x3 – x2 + 3

D).f(x) = 12x5 – 8x4 + 36x3 – 4x2 + 48

Solution:

The function given to us is:

3x5 – 2x4 + 9x3 – x2 + 12

Find the factors of 12 and consider it as 'p'

The factors of 12 are:

p = +/- 1 , +/-2 , +/-3 , +/- 4 , +/-6

Now find the factors of 3 and consider it as 'q'

The factors of 3 are:

q = +/- 1 , +/- 3

We know that we write rational terms in p/q form.

Therefore the Rational roots are given by p/q

+/- 1 , +/-2 , +/-3 , +/- 4 , +/-6 , +/- 1/3 , +/- 2/3 , +/- 4/3

Now we will solve the first function given in part A.

f(x) = 3x^5 – 2x^4 - 9x^3 + x^2 - 12

Again find the factors of 12 and consider it as 'p'

The factors are:

p = +/- 1 , +/-2 , +/-3 , +/- 4 , +/-6

Now find the factors of 3 and consider it as 'q' .

q = +/- 1 , +/- 3

Rational root are given by p/q

+/- 1 , +/-2 , +/-3 , +/- 4 , +/-6 , +/- 1/3 , +/- 2/3 , +/- 4/3

Therefore the rational roots of the given function matches the rational roots of the given equation.

Hence the correct option is A

6 0

3 years ago

Help.........................<br><br>

garri49 [273]

<h3>Answer: Choice A</h3>

$x^2\left(\sqrt[4]{x^2}\right)$

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

$\sqrt[4]{x} = x^{1/4}$

The same applies to x^10 as well

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}$

Multiply the exponents 10 and 1/4 to get 10/4

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}$

$\sqrt[4]{x^{10}} = x^{10/4}$

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

$x^{m/n} = x^a\sqrt[n]{x^b}$

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

$x^{m/n} = x^a\sqrt[n]{x^b}$

turns into

$x^{10/4} = x^2\sqrt[4]{x^2}$

which means

$\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}$

7 0

3 years ago