Answer:
Mixed fractions is equivalent to improper fraction both A and C
A. 12 1/3
C. 10 7/3
A. 1.50c+ 4.00a = 5050 (Money earned)
c + a =2200 (Guests in the museum)
The measures of the angles don't change when you translate a figure, because the entire figure is moving as a whole. Imagine having a paper parallelogram, moving it around and flipping it over. Not even dilations would change these angles (for reasons that can be pretty easily visualed but not really proven until geometry)
Answer:
a) P(Y > 76) = 0.0122
b) i) P(both of them will be more than 76 inches tall) = 0.00015
ii) P(Y > 76) = 0.0007
Step-by-step explanation:
Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
To find - (a) If a man is chosen at random from the population, find
the probability that he will be more than 76 inches tall.
(b) If two men are chosen at random from the population, find
the probability that
(i) both of them will be more than 76 inches tall;
(ii) their mean height will be more than 76 inches.
Proof -
a)
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
) >
)
= P(Z >
)
= P(Z >
)
= P(Z > 2.25)
= 1 - P(Z ≤ 2.25)
= 0.0122
⇒P(Y > 76) = 0.0122
b)
(i)
P(both of them will be more than 76 inches tall) = (0.0122)²
= 0.00015
⇒P(both of them will be more than 76 inches tall) = 0.00015
(ii)
Given that,
Mean = 69.7,
= 1.979899,
Now,
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
)) >
)
= P(Z >
)
= P(Z >
))
= P(Z > 3.182)
= 1 - P(Z ≤ 3.182)
= 0.0007
⇒P(Y > 76) = 0.0007
Answer:
A piecewise function.
Step-by-step explanation:
The problem you showed is a <em>piecewise function.</em>
In this problem, you have to plug in 3 for the value x.
However, if you take a look at the conditions that value x has, it never says that x can equal 3. <em>Thus, this function cannot be true.</em>
<em>Way to check this input is undefined: </em>
Plug in 3 for the variable x. On the first function, your output will be 4. On the second function, your output will be 8.
According to the definition of a function, a function can have many inputs but only one output. In this case, this function has one input, that is 3, but produces two outputs.