All categories

4 years ago

ASAP! PLEASE HELP MEEEE! I WILL GIVE BRAINLIEST!!!

1 answer:

4 0

The amount of the tip is approximately $7.
The actual number is 6.993, but it says round to the nearest bill. So round up to $7.

You might be interested in

Find the slope (-5,-6), (3,-3) , (−5,−6), (3,−3)

Tresset [83]

Answer:

the slope or gradient is 8/2=4

6 0

3 years ago

What is the vertex of the graph of y = –x2

dolphi86 [110]

The parabola goes down(makes a sad face) because it is negative. The answer is 0,0

6 0

3 years ago

Read 2 more answers

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

Kryger [21]

For this case we have the following functions:

$f (x) = 4 - x ^ 2\\g (x) = 6x$

The first thing we must do for this case is to subtract both functions.

We have then:

$(g - f) (x) = g (x) - f (x)$

Substituting we have:

$(g - f) (x) = (6x) - (4 - x ^ 2)$

Rewriting we have:

$(g - f) (x) = x ^ 2 + 6x - 4$

Evaluating the obtained function for x = 3 we have:

$(g - f) (3) = (3) ^ 2 + 6 (3) - 4\\(g - f) (3) = 23$

Answer:

The value of the function evaluated at x = 3 is:

$(g - f) (3) = 23$

7 0

3 years ago

Read 2 more answers

Expand and simplify. 7(2x+3) + 4(3x + 10)

Thepotemich [5.8K]

Answer:

26x+61

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

A buoy oscillates in simple harmonic motion y= A cos cos as waves move past it. The buoy moves a total of 3.5 feet (vertically)

NNADVOKAT [17]

Answer:

a) $y = 1.75 ft cos (\frac{\pi}{5}t)$

b) $v(t) = -1.0995 sin (\frac{\pi}{5}t)$

Step-by-step explanation:

Part a

Since the buoy oscillates in simple harmonic motion the equation to model this is given by:

$y = A cos (wt +\theta)$

For this case from the info given we know that:

$2A = 3.5 , A = \frac{3.5}{2}= 1.75 ft$

"It returns to its high point every 10 seconds." That means period =10 $T =10s$ , and the angular frequency can be founded like this:

$w = \frac{2\pi}{10}= \frac{\pi}{5}$

Assuming that the value for the phase is $\theta =0$ our model equation is given by:

$y = 1.75 ft cos (\frac{\pi}{5}t)$

Part b

From definition we can obtain the velocity with the derivate of the position function and if w calculate the derivate we got this:

$\frac{dy}{dt}= v(t) = -1.75 ft (\frac{\pi}{5}) sin (\frac{\pi}{5}t)$

$v(t) = -1.0995 sin (\frac{\pi}{5}t)$

6 0

3 years ago