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vesna_86 [32]
3 years ago
7

What are the like terms in 5a + 2 - 7

Mathematics
2 answers:
Blizzard [7]3 years ago
7 0
The like terms are 2 and -7
DerKrebs [107]3 years ago
4 0
The like terms are 2 and -7
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Which equation models the problem below if c represents the number of puppies whose eyes are closed?
True [87]
First you must take into account the variable that is being defined for this case:
 c = represents the number of puppies whose eyes are closed.
 We can then write the following equation:
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 Rewriting the equation:
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3 years ago
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In Triangle XYZ below, x2+y2=z2.
choli [55]

4, 2, 1, 3

we cannot use 2 before having another triangle, so 4 must be before 2

we can use 1, but it will be just a restatement of the given information is not done before 4 and 2

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Mary invests £12000 in a savings account. The account pays 1. 5% compound interest per year. Work out the value of her investmen
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4 0
2 years ago
Calculate the value of x​
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Step-by-step explanation:

5 0
2 years ago
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Prove the identity secxcscx(tanx+cotx)=2+tan^2x+cot^2x
svetlana [45]
Hello,

sec(x)= \dfrac{1}{cos(x)} \\

cosec(x)= \dfrac{1}{sin(x)} \\

sec(x)*cosec(x)*(tg(x)+cotg(x))=\dfrac{1}{cos(x)}* \dfrac{1}{sin(x)}*( \frac{sin(x)}{cos(x)} +\frac{cos(x)}{sin(x)})\\

= \dfrac{sin^2(x)+cos^2(x)}{sin^2x*cos^2x} \\

= \dfrac{1}{sin^2x*cos^2x} \\


==============================================================
2+tg^2(x)+cotg^2(x)=2+ \dfrac{sin^2x}{cos^2x} + \dfrac{cos^2x}{sin^2x} \\

=2+ \dfrac{sin^4x+cos^4x}{sin^2x*cos^2x} \\

=\dfrac{2*sin^2x*cos^2x+sin^4x+cos^4x}{sin^2x*cos^2x} \\

= \dfrac{(sin^2x+cos^2x)^2}{sin^2x*cos^2x}} \\

= \dfrac{1}{sin^2x*cos^2x}} 

8 0
3 years ago
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