(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
If its a triangle u have to add the given angles and subtract by 180 to get x
Answer:
m = -5/2
Step-by-step explanation:
Solve for slope with the following equation:
<em>m </em>(slope) = (y₂ - y₁)/(x₂ - x₁)
Let:
(4 , -12) = (x₁ , y₁)
(-2 , 3) = (x₂ , y₂)
Plug in the corresponding numbers to the corresponding variables:
<em>m </em>= (3 - (-12))/(-2 - 4)
<em>m</em> = (3 + 12)/(-2 - 4)
<em>m </em>= (15)/(-6)
Simplify the slope:
<em>m</em> = -(15/6) = -5/2
-5/2 is your slope.
~
