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ASHA 777 [7]
3 years ago
13

Can someone please help with either? will mark brainliest

Mathematics
1 answer:
mylen [45]3 years ago
4 0

Answer:

a

Step-by-step explanation:

i just did it

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NEED HELP ASAP GIVING BRAINLIST!!!!!!!
Shtirlitz [24]

(a) 8(4x+3) > -1 + 7x

32x + 24 > -1 + 7x

32x - 7x > -1 -25

25x >-26

x > -26/25

(b) 167 < 6 + 7(2 - 7r)

167 < 6 + 14 - 49r

49r < 6 + 14 - 167

49r < - 147

r < - 3

(c) 8x + 40 > -8 ( 1 - 7x)

8x + 40 > -8 + 56x

56x - 8x < 48

48x < 48

x < 1

(d)5( 6 + 3r) + 7 > 127

30 + 15r + 7 > 127

15r > 127 - 37

15r > 90

r > 6

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3 years ago
6 teaches equally share 1/2 a box of paper what fraction of the box of paper does each teacher receives ​
lilavasa [31]

Answer:

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0.5/6

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3 years ago
HELPPPP!!!! <br> Need the answer ASAP!!
Greeley [361]

<u>Given </u>that the functions f(x)=x+4 and g(x)=x^{3}

We need to determine the value of the function (g \ {\circ} f)(-3)

First, we shall determine the composition of the function (g \circ f)(x)

<u>Function </u>(g \circ f)(x)<u>:</u>

Let us determine the function (g \circ f)(x)

Thus, we have;

(g \circ f)(x)=g[f(x)]

               =g[x+4]

               =(x+4)^3

(g \circ f)(x)=x^3+3x^2(4)+3x(4)^2+(4)^3

(g \circ f)(x)=x^3+12x^2+48x+64

Thus, the function is (g \circ f)(x)=x^3+12x^2+48x+64

<u>Value of the function </u>(g \ {\circ} f)(-3)<u>:</u>

The value of the function can be determined by substituting x = -3 in the function (g \circ f)(x)=x^3+12x^2+48x+64

Thus, we have;

(g \circ f)(-3)=(-3)^3+12(-3)^2+48(-3)+64

Simplifying the terms, we get;

(g \circ f)(-3)=-27+12(9)+48(-3)+64

(g \circ f)(-3)=-27+108-144+64

(g \circ f)(-3)=1

Thus, the value of the function (g \ {\circ} f)(-3) is 1.

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3 years ago
What is the graph of the function rule y=3x+2
Nadusha1986 [10]

Answer:

in the photo is the graph

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Ben the camel drinks tea (so classy!). He drinks 350350350 liters of tea every 222 days.
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350350350*3 = 1051051050 liters of tea (that's a lot!)
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