Answer:
Promoter 2
Explanation:
Promoter 2 is the best choice because the resistance gene will only be expressed in the leaves of the corn plant. Promoter 3 only expresses genes in the corn roots, so the toxin would not be available in the leaves for the pest to eat. Promoters 1 and 4 would express the resistance gene in the leaves of the corn plant, but the toxins would be expressed in the corn cobs as well, which may then be fed to livestock.
I believe this is a trick question but all cells aside from your outer cells, skin hair ect need to be in osmotic equilibrium I believe
Answer:
0.8 and 0.2
Explanation:
Hardy Weinberg law states that the allele frequency of the population remain stable from one generation to next generation if no natural selection, drift or mutation occurs in the population.
Let p and q be the dominant and recessive frequency of the population respectively.
The dominant phenotype means p² = 0.64
p = 0.8
and we known that p + q = 1, in hardy Weinberg equilibrium.
0.8 + q = 1.
q = 0.2
Thus, the dominant allele is 0.8 and recessive allele is 0.2.
The answer to the is hypothermia
Answer:
A lethal mutation, thereby the resulting phenotype is not observed
.
Explanation:
Lethal mutations are the result of genomic changes that may be lethal in certain conditions. In genetic research, this type of mutation has shown to be very useful in analyzing gene function (i.e., genes whose protein products are key for the survival of the organism in question), and they are perfect gene markers. In bacteriophages, for example, temperature-sensitive mutants of phage T4 that can not grow at temperatures higher 42°C have been identified (Edgar & Lielausis 1964).
Citation:
R. S. Edgar, & I. Lielausis (1964). Temperature-sensitive mutants of bacteriophage T4D: their isolation and genetic characterization. Genetics, 49(4), 649.
