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2 years ago

What is the length of /AB?

Mathematics

1 answer:

Alekssandra [29.7K]2 years ago

8 0

Answer:

$\sqrt{53}$

Step-by-step explanation:

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Fill in the missing number in this sequence:<br> { } 216, 36, 6, 1

schepotkina [342]

Answer:

1296

Step-by-step explanation:

times each number by 6

example: 1x6=6 6x6=36 36x6=216 216x6=1296

8 0

1 year ago

Read 2 more answers

I need help on my warm up!! pls thx!

xxMikexx [17]

Step-by-step explanation:

$\tt{30.16 = 17.56 + 5x}$

Swap the sides of the equation :

⤑ $\tt{17.56 + 5x = 30.16}$

We want to remove the 17.56 first.

Since the original equation is 17.56 , we are going to use the opposite operation and subtract 17.56 from both sides :

⤑ $\tt{5x + 17.56 - 17.56 = 30.16 - 17.56}$

Simplify. 17.56 - 17.56 = 0 on the left. 30.16 - 17.36 = 12.6 on the right.

⤑ $\tt{5x = 12.6}$

Then, we need to think about how to remove the coefficient 5. Since the opposite of multiplication is division , I am going to divide both sides by 5.

⤑ $\tt{ \frac{5x}{5} = \frac{12.6}{5}}$

Simplify. 5/5 = 1 on the left and 12.6/5 = 2.52 on the right. So, Our answer is x = 2.52.

$\pink{ \boxed{ \boxed { \tt{Our \: final \: answer : \underline{ \underline{ \bold{ \tt{x = 2.52}}}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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7 0

2 years ago

Which of the following are true statements about any regular polygon

beks73 [17]

Answer:

need

Step-by-step explanation:

4 0

2 years ago

Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20

vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of $y=f(x)$ is a vertical has an asymptote at $x=a$ if at least one of the following statements is true:

$1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty$

The function is:

$f(x)=\frac{x^2+7x+10}{x^2+9x+20}$

First of all, let't factor out:

$f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq 5$

From here:

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty$

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty$