
Since all the variables cancel out and the coefficient equal to eachother, this system of equation has
<u>infinitely many solutions!</u>
Area of square = s^2
Area of Rectangle = lw
l = 2s
w+3 = s
solve for w, w=s-3
Now we have l and w.
Plug both into area of rectangle formula so: (2s)(s-3)
Since both areas are equal set both equations equal to each other:
(2s)(s-3)=s^2
Now simplify
2s^2-6s=s^2
s^2-6s=0, Solve for s.
Factor polynomial. s(s-6)=0 , s can be equal to 0 or 6. HOWEVER, you cannot have a side length of 0 therefore the side length has to be 6.
Now plug in s for the length formula for the rectangle:
l = 2s so... l = 2(6) so length of rectangle = 12.
Now plug in s for the width formula for the rectangle:
w+3=s so... w+3=6 so width of rectangle = 3.
Now the dimensions of the rectangle are 12 by 3. 12 being length and 3 width.
To CHECK:
Find area of rectangle:
A=lw so A=3 times 12 so A=36
Find area of square:
We know the side is equal to 6 so
A=s^2 so 6^2 = 36
The areas are equal that verifies the answer of 12 by 3.
Answer:
Answer is 1715
Step-by-step explanation:
<em>DON'T</em><em> </em><em>make</em><em> </em><em>fun</em><em> </em><em>in</em><em> </em><em>brainly</em><em>. </em>
<em>this</em><em> </em><em>app</em><em> </em><em>is</em><em> </em><em>made</em><em> </em><em>to</em><em> </em><em>help</em><em> </em><em>more students in </em><em>all</em><em> </em><em>subjects</em><em>. </em><em>whatever</em><em> </em><em>don't</em><em> </em><em>do</em><em> </em><em>the</em><em> </em><em>mistakes</em><em> </em><em>again</em><em>. </em>
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
Multiply equation B by 2.
Multiply equation A by 2
Multiply equation B by 3.
Multiply equation A by -3
Answer: D