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3 years ago

13

FIRT ONE TO ANWSER WILL BE MARKED BRAINLIEST!

2 answers:

gayaneshka [121]3 years ago

8 0

Answer:

A

..... . . .. . . . . . . . . . . .

.

user100 [1]3 years ago

5 0

Answer:

A

Step-by-step explanation:

Each poster is 1.5 feet long, so you would multiply by three to find the combined length of the posters to get 4.5. Then you would subtract that from the length of the wall which is 9, 9-4.5=4.5. Next, since you would divide by 4 because there are 4 spaces between the posters and the edges of the wall.

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Find the sum. 2x^2 +26x+ 156=0

Mila [183]

Answer:

-13

Step-by-step explanation:

2x²+26x+156=0

x²+13x+78=0

x²+13x=-78

x²+13x+169/4=-143/4

(x+13/2)²=-143/4

x+13/2=(i√143)/2 or x+13/2=-(i√143)/2

x=(i√143)/2-13/2 or x=-(i√143)/2-13/2

(i√143)/2-13/2+(-(i√143)/2)-13/2=(i√143-13-i√143-13)/2=-26/2=-13

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3 years ago

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100 points!! <br> Please solve question 50 in detail

SCORPION-xisa [38]

Answer:

2.62

Step-by-step explanation:

$log_{b} \frac{b^{2}x^{\frac{5}{2} }}{\sqrt{y}}$

First, write the square root as exponent.

$log_{b} \frac{b^{2}x^{\frac{5}{2} }}{y^{\frac{1}{2}}}$

Move the denominator to the numerator and negate the exponent.

$log_{b}(b^{2}x^{\frac{5}{2}}y^{-\frac{1}{2}})$

Use log product property.

$log_{b}(b^{2}) + log_{b}(x^{\frac{5}{2}}) + log_{b}(y^{-\frac{1}{2}})$

Use log exponent property.

$2 log_{b}(b) + {\frac{5}{2}}log_{b}(x) - {\frac{1}{2}}log_{b}(y)$

Substitute values.

$2(1) + \frac{5}{2}(0.36) - \frac{1}{2}(0.56) \\2.62$

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