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3 years ago

How can I divide decimals

2 answers:

7 0

So lets say 58 x 2.056 well you move the decimal to the side so count the numbers behind the decimal (3) and make it like 2056 x 58 then after you get the answer you move it up 3 spaces up to the left and you get 119.248

shusha [124]3 years ago

4 0

You can write the problem with a division box, move the divisor decimal point the amount of spaces that it would take to make the number whole. Move the decimal if the dividend the same amount of spaces as the divisor. Move the decimal point directly up above the division bar, divide, check your work

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Amir has $200 budget to spend on a graduation party for his son he already has purchased $122 worth of drinks and party supplies

Bas_tet [7]

Answer: C, D, and E

Step-by-step explanation:

200-122=78 remaining

A: 7*11.75= 82.25

B: 10*11.75= 117.50

C: 9*6.80=61.20

D: 11*6.80=74.80

E: 70*1.10=77.00

F: 71*1.10=78.10

Only C, D and E are below the dollars remaining in the budget.

5 0

3 years ago

Find the values of x and y<br> X =<br> Y=

labwork [276]

Answer:

Find the values of x and y

X =60

Y=60

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3 0

2 years ago

140 subtracted from the square of a number the result is three times the number find the negative solution

natima [27]

Answer:

$Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.$

5 0

2 years ago

Need help!!! i also have similar question to this one too if you want to help me. :)

natta225 [31]

Answer:

19 pts

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

In order to solve the following system of equations by addition, which of the following could you do before adding the equations

alexandr402 [8]

To solve the question, the both equations should have a positive value and a negative value with same number. Then one variable can be eliminated.

To eliminate X term first, we should multiply the first equation by 2 and second one by 3.
Then,
6X - 12Y = -30
-6X + 15Y = 70

Or

To eliminate Y term first, we should multiply the first equation by 5 and second one by 6.
Then,
15X - 30Y = -75
-12X + 30Y = 84

According to the choices given 'A' is the correct answer.

5 0

3 years ago