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3 years ago

Given the two expressions shown below:

Mathematics

2 answers:

alexgriva [62]3 years ago

5 0

Answer:

just here for da points babes have a nice night or day :p

Tanya [424]3 years ago

3 0

C is the answer c is the answer

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Write an equation for an ellipse centered at the origin, which has foci at (\pm8,0)(±8,0)left parenthesis, plus minus, 8, comma,

mario62 [17]

Answer:

The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

Step-by-step explanation:

The standard form of the equation of an ellipse with center (0 , 0) is

$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ , where

The coordinates of the vertices are (± a , 0)

The coordinates of the foci are (± c , 0) , where c ² = a² - b²

∵ The ellipse is centered at the origin

∴ The center of it is (0 , 0)

∵ It has foci at (± 8 , 0)

- The coordinates of the foci are (± c , 0)

∴ c = ±8

∵ It has Vertices at (± 17 , 0)

- The coordinates of the vertices are (± a , 0)

∴ a = ±17

∵ c² = a² - b²

- Substitute the values of c and a to find b

∴ (8)² = (17)² - b²

∴ 64 = 289 - b²

- Add b² to both sides

∴ b² + 64 = 289

- Subtract 64 from both sides

∴ b² = 225

- Take √ for both sides

∴ b = ± 15

∵ The equation of the ellipse is $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$

- Substitute the values of a and b in it

∴ $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$ ⇒ $\frac{x^{2}}{289}+\frac{y^{2}}{225}=1$

∴ The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

6 0

3 years ago

10 points, doing this one again because I got a wrong answer last time but regardless thank you for trying to help

Alik [6]

Hey ! there

Answer:

Value of missing side i.e. TE is 12 feet

Step-by-step explanation:

In this question we are provided with a right angle triangle having TS - 35 ft and SE - 37 ft . And we are asked to find the missing side that is TE using Pythagorean Theorem .

Pythagorean Theorem : -

According to Pythagorean Theorem sum of squares of perpendicular and base is equal to square of hypotenuse in a right angle triangle i.e.

H² = P² + B²

Where ,

H refers to Hypotenuse

P refers to Perpendicular

B refers to Base

Solution : -

In the given triangle ,

Base = TE

Perpendicular = TS ( 35 feet )

Hypotenuse = SE ( 37 feet )

Now applying Pythagorean Theorem :

$\quad \longmapsto \qquad \:SE {}^{2} = TS {}^{2} + TE {}^{2}$

Substituting values :

$\quad \longmapsto \qquad \:37 {}^{2} = 35 {}^{2} + TE {}^{2}$

Simplifying it ,

$\quad \longmapsto \qquad \:1369 = 1225 + TE {}^{2}$

Subtracting 1225 on both sides :

$\quad \longmapsto \qquad \:1369 - 1225 = \cancel{1225} + TE {}^{2} - \cancel{1225}$

We get ,

$\quad \longmapsto \qquad \:144 = TE {}^{2}$

Applying square root to both sides :

$\quad \longmapsto \qquad \ \sqrt{ 144} = \sqrt{TE {}^{2}}$

We get ,

$\quad \longmapsto \qquad \: \red{\underline{\boxed{\frak{TE = 12 \: feet}}}} \quad \bigstar$

Henceforth , value of missing side is 12 feet .

Verifying : -

Now we are verifying our answer using Pythagorean Theorem . We know that according to Pythagorean Theorem ,

SE² = TS² + TE²

Substituting value of SE , TS and TE :

37² = 35² + 12²

1369 = 1225 + 144

1369 = 1369

L.H.S = R.H.S

Hence , Verified .

Therefore , our answer is correct .

<h2>#Keep Learning</h2>

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Robin went on 4 rides

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1 year ago

What is the solution to the following system of

Rufina [12.5K]

Answer:

i think the correct answer of these qusion is -2,3

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