Answer:
The approximate are of the inscribed disk using the regular hexagon is 
Step-by-step explanation:
we know that
we can divide the regular hexagon into 6 identical equilateral triangles
see the attached figure to better understand the problem
The approximate area of the circle is approximately the area of the six equilateral triangles
Remember that
In an equilateral triangle the interior measurement of each angle is 60 degrees
We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon
Let
M ----> the mid-point of AB
OM ----> the perpendicular bisector of AB
x ----> the measure of angle AOM

In the right triangle OAM

so

we have

substitute

Find the area of six equilateral triangles
![A=6[\frac{1}{2}(r)(a)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28r%29%28a%29%5D)
simplify

we have

substitute

Therefore
The approximate are of the inscribed disk using the regular hexagon is 
Step-by-step explanation:
answer is 22 students in the team
<em>how </em><em>do </em><em>u </em><em>get </em><em>it? </em>
you know it is 80% of the students went for try out so you do 100% - 80% give you 20% students the number of students in the team already. so you do 20 / 100 x 110 students which already in the whole school over 1 which would give it 22
Answer:
X=17
Step-by-step explanation:
AC^2=AB^2 +BC^2(PYTHAGOREAN THEORM)
100=64 +BC^2
36=BC^2
6CM=BC
AD^2=AB^2+BD^2(PYTHAGOREAN THEORM)
X^2 =64+225
X^2=289
X=17
<span>Let x equal the repeating decimal you are trying to convert to a fraction.Examine the repeating decimal to find the repeating digit(s)<span>Place the repeating digit(s) to the left of the decimal point.</span></span>