If you are looking for the expanded version, this is it. It is also possible to group either an a from (a^2 + 2b) or a b from (2ab + b^2). Hope this helps!
Answer:
no it is not a solution.READ THE WHOLE EXPLANATION! IT WILL HELP WITH THE OTHER PROBLEMS!!!!
Step-by-step explanation:
when something like (1,6) is written consider it as (x,y). in this case, 1 is considered as x, and 6 is considered as y. if you substitute these number for x and x and y, (x =1 and y =6), you'll see that the equation will go from y=x +7, to 6=1+7. Which is not true.
It’s not a function because the domain (the X) is repeating...
X cannot repeat if you want it to be a function
<span>z2 – 2z – 35 = 0
2z - 2z = 35
0 = 35
No solution</span>
