5.7 divided by 8 plss answer quick
2 answers:
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Answer:
Here is the complete question attached with.
The mean score would decrease more than the median score.
Step-by-step explanation:
The numbers for which we have to find the mean and median are:
Here the mean,
Median, as median is the middle term if the observations are arranged in ascending order.
Now as the question says that we have to add a zero to see its effect.
So adding a zero we have
Mean
Median ,as number of observations is even terms so we will add two middle numbers and divide it with
.
So we can conclude that the mean is having more variation than the median.
Mean shows as variation of where as Median shows a variation of
only.
So our final answer is option D that is "The mean score would decrease more than the median score."
An expression for this timet-half will be given as ln(2) / λ ≈ 0.693 / λ
<h3>What is an expression?</h3>
Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.
The complete question is:
Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:
N(t)=No e−λt,
where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.
Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.
Express your answer in terms of N0 and/or λ.
1) Equation given:
← I used α instead of λ just for editing facility..
Where No is the initial number of nuclei.
2) Half of the initial number of nuclei: N (t-half) = No / 2
So, replace in the given equation:
3) Solving for α (remember α is λ)
αt ≈ 0.693
⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ
Therefore expression for this timet-half will be given as ln(2) / λ ≈ 0.693 / λ
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