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Travka [436]
3 years ago
5

Use a common denominator What does 1/9 equal?

Mathematics
1 answer:
dem82 [27]3 years ago
8 0

Answer:

2/18

Step-by-step explanation:

because i multiplied 1/9 by 2

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The cell phone plan from Company C costs $10 per month, plus $15 per gigabyte for data used. The plan from Company D costs $80 p
Eddi Din [679]

Answer:

C(g) = 10 + 15g

C'(g) = 80

The monthly charges of Company C for using 2 Gigabyte of data usage.

Step-by-step explanation:

The cell phone plan from Company C costs $10 per month, plus $15 per gigabyte for data used. The plan from Company D costs $80 per month, with unlimited data.

Now, the monthly cost in Company C for using g gigabyte of data will be  

C(g) = 10 + 15g ........ (1)

Again, the monthly cost in Company D for using g gigabyte of data will be  

C'(g) = 80 ......... (2)

Now, from equation (1), the statement C(2) = 10 + 15 × 2 = 40, means that monthly charges of Company C for using 2 Gigabyte of data usage. (Answer)

4 0
3 years ago
A pool is being drained at a rate of 120 gallons per minute.What is this rate in quarts per hour?
zysi [14]
There are 4 quarts in 1 gallon, so a rate of 120 gallons per minute converts to 4 x 120 = 480 quarts per minute. To find the per hour rate, we simply multiply our per minute rate by 60, obtaining 480 x 60 = 28800 quarts per hour.
7 0
2 years ago
Un dirigible que está volando a 800 m de altura, distingue un pueblo con un ángulo de depresión de 12°. ¿A qué distancia del pue
alexira [117]

Answer:

3764 m

Step-by-step explanation:

Resolvemos usando la función trigonométrica de tangente.

tan θ = Opuesto / Adyacente

θ = Ángulo de depresión = 12 °

Opuesto = 800m

Adyacente = Distancia de la ciudad = x

Cruz multiplicar

bronceado 12 = 800 / x

Cruz multiplicar

bronceado 12 × x = 800

x = 800 / tan 12

x = 3763.7040876 m

Aproximadamente = 3764 m

6 0
2 years ago
Where do I put the parentheses for this question 5•2+3-8=17
MatroZZZ [7]

Answer:

HA HATDOGGGGGGGGG G Haha cjar

4 0
2 years ago
Read 2 more answers
What is the length of RS.
Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

RP² = PQ²+RQ²

R² = r²+RQ²

RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0
3 years ago
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