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OLEGan [10]
3 years ago
13

Find the equation of the line that is perpendicular to y = 2x + 8

Mathematics
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

\boxed {\boxed {\sf B. \ y= - \frac{1}{2} x-4}}

Step-by-step explanation:

We are given the line y=2x+8. It is in slope-intercept form or y= mx+b, where m is the slope and b is the y-intercept.

The slope of the line is 2.

We want to find the equation that is perpendicular. Perpendicular lines have negative reciprocal slopes.

1. Negate

  • Negate the slope, or switch the sign
  • (+) 2 --> -2

2. Reciprocal

  • Flip the numerator and denominator of the slope.
  • -2/1 --> -1/2

The perpendicular slope is -1/2, so the correct equation must be B.

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Can anyone help with number 9 please
photoshop1234 [79]

Answer:

A) 55

Step-by-step explanation:

angle 3 is an exterior angle. to find the interior angle of the triangle, subtract angle 3 from 180

180 - 110 = 70

all the angles in a triangle add up to 180.

since angles 1 and 2 are the same, you can call them x.

70 + 2x = 180

70 - 70 + 2x = 180 - 70

2x = 180 - 70

2x = 110

2x/2 = 110/2

x = 110/2

x = 55

7 0
3 years ago
Read 2 more answers
-9 is less than or equal to x and 7 is greater than or equal to x
const2013 [10]
Plot a point at "-9" and the other at "7". Both dots will be shaded in.
8 0
3 years ago
1. (4,-3);(5,0)
saveliy_v [14]

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love

6 0
3 years ago
Watch help video
just olya [345]

Answer: 53

Step-by-step explanation:

8 0
3 years ago
Let u = &lt;-9, 4&gt;, v = &lt;8, -5&gt;. Find u - v. <br> URGENT
Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle

the subtraction is simply

u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle

So, in your case, we have

\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle

3 0
3 years ago
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