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iragen [17]
3 years ago
15

The coefficient of determination of a set of data points is 0.93 and the slope of the regression line is -5.26. Determine the li

near correlation coefficient of the data.
Mathematics
1 answer:
skad [1K]3 years ago
6 0

Answer:

- 0.964

Step-by-step explanation:

Given that Coefficient of determination (R^2) = 0.93

Slope of regression line = - 5.26

The linear correlation Coefficient =?

The Coefficient of determination (R^2) is used to obtain the proportion of explained variance of the regression line. It is the square of the linear correlation Coefficient (R).

Hence. To obtain the linear correlation Coefficient (R) from the Coefficient of determination (R^2); we take the square root of R^2

Therefore,

R = √R^2

R = √0.93

R = 0.9643650

R = 0.964

However, since the value of the slope is negative, this depicts a negative relationship between the variables, hence R will also be negative ;

Therefore, R = - 0.964

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Answer A is the correct one :)
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3 years ago
154 and 145 to the nearest hundred
Yuki888 [10]

Answer: 154: 200 145: 100

Step-by-step explanation:

If the number next to the place value is 5 or more you round it up. Like I did 154. But if the number is less that 5 you put everything to zero EXCEPT for the place value you are rounding. Good Luck

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Jake and Erica were solving a system of equations. They both noticed that the two lines had the same slope. Jake said that becau
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3 years ago
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I JUST WANNA PASS MY SOPHOMORE YEAR BUT I SUCK AT MATH!!!!! PLEASE HELP!!!!!!
Natasha2012 [34]

Mr. Sanchez's class: 1.65p

Mr. Kelly's class: 1.36j

where p = fruit pies and j = fruit juice

____________________________________________________________

(a) Creating a system of equations

p + j = 79

1.65p + 1.36j = 118.17

are your system of equations

____________________________________________________________

(a) Solving the system of equations for p and j

Solve for p in the first equation. Subtract j from both sides.

p = 79 - j

____________________________________________________________

Plug p into the second equation.

1.65(79 - j) + 1.36j = 118.17

Distribute 1.65 inside the parentheses.

130.35 - 1.65j + 1.36j = 118.17

Combine like terms.

130.35 - 0.29j = 118.17

Subtract 130.35 from both sides.

-0.29j = -12.18

Divide both sides by -0.29.

j = 42

____________________________________________________________

Plug j into the first equation.

p + (42) = 79

Subtract 42 from both sides.

p = 37

____________________________________________________________

(b) To find out how much each class earned

Now plug in p and j into Mr. Sanchez's class and Mr. Kelly's class equations (at the top).

Mr. Sanchez's class: 1.65(37) = 61.05

Mr. Kelly's class: 1.36(42) = 57.12

____________________________________________________________

(c) To see how much more Mr. S's class earned

Subtract 57.12 from 61.05.

61.05 - 57.12 = 3.93

____________________________________________________________

(a)

p + j = 79

1.65p + 1.36j = 118.17

(b)

Mr. Sanchez's class earned more money (61.05 > 57.12).

(c)

Mr. Sanchez's class earned $3.93 more than Mr. Kelly's class.

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