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icang [17]
2 years ago
10

2/5x + 4 = 1/4x. Find x

Mathematics
1 answer:
irina1246 [14]2 years ago
4 0

Answer:

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

Exact Form:

x =  − 80 /3

Decimal Form:

x = −  26.  ¯

            6

Mixed Number Form:

x = − 26  2

          ----

           3

You might be interested in
2^5×8^4/16=2^5×(2^a)4/2^4=2^5×2^b/2^4=2^c<br>A=<br>B=<br>C= <br>Please I'm gonna fail math
aleksley [76]

9514 1404 393

Answer:

  a = 3, b = 12, c = 13

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

___

You seem to have ...

  \dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)

_____

<em>Additional comment</em>

I find it easy to remember the rules of exponents by remembering that <em>an exponent signifies repeated multiplication</em>. It tells you how many times the base is a factor in the product.

  2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}

Multiplication increases the number of times the base is a factor.

  (2\cdot2\cdot2)\times(2\cdot2)=(2\cdot2\cdot2\cdot2\cdot2)\\\\2^3\times2^2=2^{3+2}=2^5

Similarly, division cancels factors from numerator and denominator, so decreases the number of times the base is a factor.

  \dfrac{(2\cdot2\cdot2)}{(2\cdot2)}=2\\\\\dfrac{2^3}{2^2}=2^{3-2}=2^1

5 0
2 years ago
3. What is the distance between -49 and 167?
Salsk061 [2.6K]

Answer:

c) IS THE ANSWER

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
The domain of u(x) is the set of all real values except 0 and the domain of v(x) is the set of all real values except 2. What ar
beks73 [17]

Answer:

A≈1075.21

d Diameter

37

d

r

r

r

d

d

C

A

Using the formulas

A=

π

r

2

d=

2

r

Solving forA

A=

1

4

π

d

2

=

h1

4

π

37

2

≈

1075.21009

Step-by-step explanation:

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%7D%20%20%3D%20%7B27%7D%5E%7B%3F%7D%20" id="TexFormula1" title=" \sqrt{3} = {27
marishachu [46]

Let the unknown be x


\sqrt{3}  = 27^x


3^\frac{1}{2}  = 3^{3x}


Both the base number are 3, so we equate the exponent:


\dfrac{1}{2}  = 3x


x = \dfrac{1}{2}  \div 3


x = \dfrac{1}{2}  \times \dfrac{1}{3}


x = \dfrac{1}{6}


Answer: 1/6


3 0
3 years ago
PLEASE HELP ME WITH THIS PROBLEM!!
Veronika [31]
Your answer would be 24, so you got it right.

This is because you need to find the lowest common multiple of 6 and 8, that is, the lowest number that divides by both 6 and 8.

We can do this by either writing out the multiples of 6 and 8 until you find a common one, or you can find the prime factors of 6 and 8 and multiply them:

6-> 3 × 2
8-> 2 × (4)->2 × 2

So we would need to do 3 × 2 × 2 × 2 = 3 × 8 = 24

I hope this helps!
4 0
3 years ago
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