Answer:
4.27%
Step-by-step explanation:
We have been given that college students average 8.6 hours of sleep per night with a standard deviation of 35 minutes. We are asked to find the probability of college students that sleep for more than 9.6 hours.
We will use z-score formula to solve our given problem.

z = z-score,
x = Random sample score,
= Mean,
= Standard deviation.
Before substituting our given values in z-score formula, we need to convert 35 minutes to hours.




Now, we need to find
.
Using formula
, we will get:

Using normal distribution table, we will get:



Therefore, 4.27% of college students sleep for more than 9.6 hours.
Answer:
I hope this helps!
Step-by-step explanation:
ACB
This looks confusing. Can you try reposting this to make it look clear?
a = The cost of the pizza.
b = The cost of the pizza and sales tax.
f(a) = The cost of the pizza.
g(b) = The cost of the pizza and sales tax.
g(f(a)) = The cost of the pizza, sales tax, and delivery fee
Ones that never intersect