Answer:
2.56
Step-by-step explanation:
Answer: 0.3077
Explanation: In a standard deck of cards, there are 52 cards. They are broken down into suits (4 of them: Spades, Hearts, Diamonds, Clubs) of 13 cards each. Each suit has 13 ordinal cards (A, 2 through 10, Jack, Queen, King).
Here we're asked to draw a card at random and find the probability of drawing either a diamond or a 7.
With probability, we look at the fraction of ways we can achieve some condition (the numerator) over the number of ways we can do something (the denominator).
Our denominator here is 52 - the number of cards from which we can pull 1.
Our numerator is both all the diamonds, 13 cards, and all the sevens, 4 cards, but we need to subtract 1 to account for the double counting of the 7 of diamonds.
In all we get: 13+4−1/52=16/52=4/13≈0.3077
Hope this helps... Stay safe and have a great day/night!!!
The answer is 8 I believe
Answer:
2√2 / 3 (first answer choice)
Step-by-step explanation:
If tan Ф < 0, then Ф must be in either Quadrant II or Quadrant IV.
If sin Ф = +1/3, then Ф (for this problem) is in Quadrant II.
Remembering that sin Ф = opp / hyp = 1 / 3, we use the Pythagorean Theorem to find the adj side:
adj² + 1² = 3², or
adj² + 1 = 9, or adj² = 8. Since Ф is in Quadrant II, adj is negative.
The value of cos Ф = adj / hyp = √8 / 3 = 2√2 / 3
29) 1/2
30) 3/5
31) 3/4
32) 8/10 equal 4/5
33 not sure
