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sukhopar [10]
3 years ago
10

A regular nonagon has a perimeter of 36 cm and an

Mathematics
1 answer:
aniked [119]3 years ago
6 0

Answer:

2.56

Step-by-step explanation:

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Answer:

oki...whats the question?

Step-by-step explanation:

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⚠️⚠️please answer⚠️⚠️
Maurinko [17]

Answer:

The slope is -3/4 and the y-intercept is 1.

Step-by-step explanation:

B is the point where the line cross the y-axis, or vertical axis. Slope is the steepness of the line. Determined by rise over run. When the slope goes down 3 units, the slope goes to the right 4 units.

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3 years ago
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The mass of the eggs laid by a certain breed of hen is a normally distributed random variable with mean 0.06kg and standard devi
Olin [163]

a (i) The number of standard size is 288 eggs

a (ii) The number of medium size is 1,476 eggs

a (iii) The number of large size is 36 eggs

b (i) The expected profit made from selling the standard size is Gh¢43.2

b (ii) The expected profit made from selling the medium size is Gh¢516.6

b (iii) The expected profit made from selling the large size is Gh¢16.2

The given parameters:

the mean of the distribution, m = 0.06 kg

standard deviation (std) of the distribution, d = 0.009 kg

number of the samples, n = 1800 eggs

(i) Find the position of "less than 0.052 kg (standard size)":

  • 1 standard deviation below the mean = m - d
  • m - d = 0.06 kg  -  0.009 kg = 0.051 kg

(<em>the </em><em>standard size</em><em> is 1 standard deviation below the mean</em>)

  • less than 1 standard deviation below the mean in a normal distribution is equal to 16% of the data samples
  • Number of standard size = 0.16 x 1800 = 288 eggs

(ii) Find the position of "Between 0.052 kg and 0.075kg (medium size)":

  • 0.052 kg is 1 standard deviation below the mean
  • 2 standard deviation above the mean = m + 2d
  • m + 2d = 0.06 + 2(0.009) = 0.078 kg

(<em>the </em><em>medium size</em><em> is between 1 std below the mean and 2 std above the mean</em>)

  • Between 1 std below the mean and 2 std above the mean in a normal distribution = (68 + 14)% = 82%
  • Number of medium size = 0.82 x 1800 = 1,476 eggs

(iii) Find the position of "Greater than 0.075 kg (large size)":

  • 0.078 kg is 2 standard deviation below the mean
  • greater than 2 std above the mean in a normal distribution = 2 % of the data samples
  • Number of large size = 0.02 x 1800 = 36 eggs

<u>Check:</u> <em>288 eggs + 1476 eggs + 36 eggs = 1,800 eggs</em>

(b) the cost of production of an egg = Gh¢0.45

the selling price of the standard size = Gh¢0.60

the selling price of the medium size = Gh¢0.80

the selling price of the large size = Gh¢0.95

(i) The expected profit made from selling the standard size:

Profit = total revenue - cost of production

Profit = 288(0.6) - 288(0.45) = Gh¢43.2

(ii) The expected profit made from selling the medium size:

Profit = total revenue - cost of production

Profit = 1476(0.8) - 1476(0.45) = Gh¢516.6

(iii) The expected profit made from selling the large size:

Profit = total revenue - cost of production

Profit = 36(0.9) - 36(0.45) = Gh¢16.2

Learn more here: brainly.com/question/22520030

3 0
3 years ago
This is factoring trinomials,help plz!
MaRussiya [10]
10.
Factor the following:
8 x^2 - 2 x - 10
Factor 2 out of 8 x^2 - 2 x - 10:
2 (4 x^2 - x - 5)

Factor the quadratic 4 x^2 - x - 5. The coefficient of x^2 is 4 and the constant term is -5. The product of 4 and -5 is -20. The factors of -20 which sum to -1 are 4 and -5. So 4 x^2 - x - 5 = 4 x^2 - 5 x + 4 x - 5 = 4 x (x + 1) - 5 (x + 1):
2 4 x (x + 1) - 5 (x + 1)
Factor x + 1 from 4 x (x + 1) - 5 (x + 1):
Answer:  2 (x + 1) (4 x - 5)
_____________________________________________

13. 
Factor the following:
16 x^2 - 24 x + 8

Factor 8 out of 16 x^2 - 24 x + 8:
8 (2 x^2 - 3 x + 1)

Factor the quadratic 2 x^2 - 3 x + 1. The coefficient of x^2 is 2 and the constant term is 1. The product of 2 and 1 is 2. The factors of 2 which sum to -3 are -1 and -2. So 2 x^2 - 3 x + 1 = 2 x^2 - 2 x - x + 1 = -(2 x - 1) + x (2 x - 1):
8 x (2 x - 1) - (2 x - 1)

Factor 2 x - 1 from x (2 x - 1) - (2 x - 1):
Answer: 8 (2 x - 1) (x - 1)
8 0
3 years ago
Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start
Kamila [148]

Option B: \frac{1}{(m-4)(m-3)} is the correct answer.

Explanation:

The given expression is \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}

Simplifying the expression, we have,

\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}

Factor the equations, m^{2}-16\right and m^{2}-9,we get,

m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)

m^{2}-9=m^{2}-3^2=(m+3)(m-3)

Substituting these factored expressions in the above expression, we have,

\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}

Cancelling the common terms m+3 and m+4 , we get,

\frac{1}{(m-4)(m-3)}

Thus, the expression equivalent to \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )} is \frac{1}{(m-4)(m-3)}

Hence, Option B is the correct answer.

3 0
3 years ago
Read 2 more answers
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