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devlian [24]
3 years ago
15

I NEED HELP AND QUICK.

Mathematics
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

1. 40-p+w

2. $4 left

I'm not sure about the first one, but I'm pretty sure about the second one.

Step-by-step explanation:

You might be interested in
Solve each inequality and graph the solution on a
Law Incorporation [45]

The solution for the first inequality is a ≥ 2 or a ∈ [2, ∞), and for the second inequality the solutions are b < -5 or b ∈ (-∞, -5)

<h3>What is inequality?</h3>

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have two inequalities:

a.) -12a +7 ≤31

b.) -9 > 3b +6

a)  -12a +7 ≤ 31

-12a ≤ 31 - 7

-12a ≤ 24

-a ≤ 2

a ≥ 2  (sign changed because multiplied by a negative number)

a ∈ [2, ∞)

b.) -9 > 3b +6

-15 > 3b

-5 > b

or

b < -5

b ∈ (-∞, -5)

Thus, the solution for the first inequality is a ≥ 2 or a ∈ [2, ∞), and for the second inequality the solutions are b < -5 or b ∈ (-∞, -5)

Learn more about the inequality here:

brainly.com/question/19491153

#SPJ1

7 0
2 years ago
A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 33003300 tickets overall. It h
Lina20 [59]

Answer:

Number of each ticket is;

$10 tickets = 1115

$20 tickets = 1251

$30 tickets = 934

Step-by-step explanation:

Let x,y and z represent the number of $10,$20 and $30 tickets sold.

Given;

Total number of tickets n = 3300

x+y+z = 3300 .....1

Total sales = $64,190

10x + 20y + 30z = 64,190 .....2

It has sold 136 more​ $20 tickets than​ $10 tickets

y = x +136 ........3

Substituting equation 3 into equation 1 and 2;

For 1;

x+y+z = 3300

x+(x+136)+z = 3300

2x + z = 330-136

2x + z = 3164 ........4

For 2;

10x + 20y + 30z = 64,190

10x + 20(x+136) + 30z = 64,190

10x + 20x + 2720 + 30z = 64190

30x + 30z = 64190-2720

30x+30z = 61470

divide through by 30

x+z = 2049 ......5

Subtract equation 5 from 4

2x-x +z-z = 3164-2049

x = 1115

From equation 3

y = x + 136 = 1115+136

y = 1251

From equation 1;

z = 3300 - (x+y)

z = 3300- (1115 + 1251)

z = 934

Number of each ticket is;

$10 tickets = 1115

$20 tickets = 1251

$30 tickets = 934

6 0
4 years ago
Kina's mother decided to increase her pocket money by 40%. How much extra did Kina receive each week if previously she had been
sleet_krkn [62]

Answer:

$560

Step-by-step explanation:

10% of $400 is $40. 40% of $400 is 10%x4. 40% of $400 is $160. Since her allowance increased by $160, it is now $560 per week.

6 0
2 years ago
Read 2 more answers
HELP TIMED!!<br> WILL GIVE BRAINLIEST
3241004551 [841]
It’s b my ninjas pog
5 0
3 years ago
Plz Help I do not understand this
loris [4]

Hello,

So Y variable is what you would start with.


20 <= he'll start off with for a

40 <= what he'll start off with for b




And X variables would be the # of hours you're working.


10 <= meaning every hour worked is worth 10 dollars

5 <= meaning every hour worked will be paid 5 dollars



So let's just say for option a he works two hours

(Option A)

10 (2) + 20

20 + 20

= 40


(Option B)

5 (2) + 40

10 + 40

50



As for your equations

Y = 10x + 40


Y= 5x + 40



3 0
3 years ago
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