Answer:
The ratio of the drag coefficients
is approximately 0.0002
Step-by-step explanation:
The given Reynolds number of the model = The Reynolds number of the prototype
The drag coefficient of the model,
= The drag coefficient of the prototype, 
The medium of the test for the model,
= The medium of the test for the prototype, 
The drag force is given as follows;

We have;

Therefore;







= (1/17)^3 ≈ 0.0002
The ratio of the drag coefficients
≈ 0.0002.
Your answer is n=2. thank me if this helped you. :)
Hello from MrBillDoesMath!
Answer:
1/ 91.4
Discussion:
Evaluate 1/ ( 3x^3 + 5.2y) when x = 3, y = 2.
1/ (3 (3)^3 + 5.2(2)) =
1/ ( 3 * 27 + 10.4) =
1/ ( 81 + 10.4) =
1/ (91.4) =
.0109 (approx)
Thank you,
MrB
Well we know that 10 and 3/4 is equivalent to 10.75. If we divide the meat into 8 equal packages we have to divide 10.75 by 8. Dividing 10.75 by 8 gives us 1.34375 pounds of meat per package. If we take that, and multiply it by our given value of $3.40 per pound, we end up getting $4.57 a package.