Suppose that equation of parabola is
y =ax² + bx + c
Since parabola passes through the point (2,−15) then
−15 = 4a + 2b + c
Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c
Since parabola passes through the point (−3,−5), then
−5 = 9a − 3b + c
Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5
Solving it we get that
a = −2, b = −4, c = 1
Thus, equation of parabola is
y = −2x²− 4x + 1
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Rewriting in the form of
(x - h)² = 4p(y - k)
i) -2x² - 4x + 1 = y
ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)
iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)
iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)
v) -3(x + 7/6)² = y - 445/36
vi) (x + 7/6)² = -⅓(y - 445/36)
(Shifting -⅓ to RHS)
vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p)
So, after rewriting the equation would be -
(x + 7/6)² = 4(-⅛)(y - 445/36)
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I hope this is what you wanted.
Regards,
Divyanka♪
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Answer:
surface area of the smaller figure ≈ 1474.64 m²
Step-by-step explanation:
The figures are similar base on the question . The surface area and the volume of the larger figure is given while only the figure of the smaller figure is given.
To find the surface area of the smaller figure we simply use the ratios. That is the scale factors.
Therefore, they are similar figure the scale factor can be represented as a:b.
The scale factor for volume is cubed.
volume of larger figure/volume of the small figure = a³/b³
4536/2625 = a³/b³
a/b = 16.5535451/13.7946209
Note that for two similar solid with scale factor a:b the surface area ratio is a²: b² (the scale factor is square)
16.55²/13.79² = 2124/x
273.9025/190.1641 = 2124/x
cross multiply
273.9025x = 403908.54840
x = 403908.54840/273.9025
x = 1474.6435261
x ≈ 1474.64 m²
