Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
D- 4 is your correct answer :)
Hope this helps
Since 7 is greater than 5, the 9 gets rounded. It would be 12.0.
The true statement about the distribution of any variable model around the mean is (D) The distribution of the variable is the same shape as the distribution of its residual
<h3>The true statement about the
distribution</h3>
From the question, we understand that the distribution of the model is based on its mean or average value.
The above means that the upper and the lower deviations are balanced.
Hence, the true statement about the distribution of any variable model around the mean is (D)
Read more about distribution at:
brainly.com/question/15713806
Answer:
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