we have
the solution is the interval -------> (3,∞)
therefore
the answer in the attached figure
This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
Answer: …………..
Step-by-step explanation:
……………..
<h3><u>Distance travelled each day is</u> : </h3>
<h3><u>Explanation</u> : </h3>
Distance travelled in 14 days is : 456.4 km
And if he travels same Distance each day, so let the Distance travelled on each day be x
According to question ~
So, he travels 32.6 km per day
