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3 years ago

Mr. Naxvip wrote the expression below to represent the number of

Mathematics

1 answer:

aliya0001 [1]3 years ago

4 0

Answer:

Step-by-step explanation:

b×3+5-1

=5×3+5-1

= 19

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Help pls , will mark first answer brainliest. which graph represents the equation in the pictures?

Gekata [30.6K]

There is only one graph

8 0

2 years ago

Y=2x-5 3x+8y+32=56 What does y and x equal?

AVprozaik [17]

Y = 2x - 5
3x + 8y + 32 = 56
3x + 8(2x - 5) + 32 = 56
3x + 8(2x) - 8(5) + 32 = 56
3x + 16x - 40 + 32 = 56
19x - 8 = 56
 + 8 + 8
 19x = 64
 19 19
 x = 3.4
y = 2(3.4) - 5
y = 6.8 - 5
y = 1.8
(x, y) = (3.4, 1.8)

5 0

2 years ago

Which statement correctly compares the mean number of students for the data in the plots?

satela [25.4K]

Answer:

"There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."

Step-by-step explanation:

We need to compute the mean for each.

Poplar Middle School:

Lets list the numbers

20,20,20,21,21,21,21,21,22,22,22,22,22,22,22,23,23,23,23,24

The average is sum of all divided by number of numbers, that will be:

435/20 = 21.75

Oak Middle School:

The numbers are:

20,21,21,22,22,23,23,23,23,24,24,24,25,25,26,26,27,27,28,29

The average is sum divided by number of numbers, that will be:

483/20 = 24.15

The difference in mean is:

24.15 - 21.75 = 2.4

We can say, that is about 2 more students in Oak Middle School, correct answer choice is "2nd answer choice" - "There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."

7 0

3 years ago

Sally walked 3/4 mile east from her house to the bank, then she walked 1/3 mile west to the gift shop. From the gift shop she wa

Verdich [7]

.333333333 and so on

3 0

3 years ago

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$

7 0

2 years ago