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Shtirlitz [24]
3 years ago
13

Someone please help me, i’ll mark brainliest answer !

Mathematics
1 answer:
igomit [66]3 years ago
6 0

Answer:

I say that the answer is A, B, and C. I'm not positive but I think that is the answer.

Step-by-step explanation:

Tell me if I'm wrong it might just be B and C.

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Cate has 10 dolls. Shelayna has 3 times as many dolls as Cate. How many more dolls does Shelayna have compared to Cate?
stiv31 [10]
Shelayna has 3 times as many dolls.

3*10=30

Cate has 10.

30-10=20 <=== Shelayna has 20 more dolls than Cate.

I hope this helps!
~kaikers
8 0
3 years ago
Can you use simplest form to compare 8/10 and 3/5 explain
jolli1 [7]
Simplify 8/10
(4*2)/(5*2)
2/2=1

Thus,
8/10=4/5

Now, compare 4/5 and 3/5.
Hope this helps!

3 0
3 years ago
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Can someone please help me with this? <br><br> What is the volume of this sphere?
lara [203]
26 feet queen your welcome
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3 years ago
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What is the sqare root of 81 pls help​
nexus9112 [7]
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5 0
3 years ago
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Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0
3 years ago
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