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algol [13]
3 years ago
6

Use slopes to determine if the lines -7x-2y=-8 and 2x+7y=-3 are perpendicular or not

Mathematics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

Since slopes of both lines are not negative reciprocals. Therefore Lines are not perpendicular to each other

Step-by-step explanation:

Slope of -7x-2y=-8 is -7/2

Slope of 2x+7y=-3 is -2/7

For perpendicular lines slopes are negative reciprocals of each other

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Find all the zeros of the equation 12x^2-64=-x^4
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Answer: all the zeroes of the above equation will be

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Step-by-step explanation:

Since we  have given that

12x^2-64=-x^4\\\\x^4+12x^2-64=0

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x^4+12x^2-64=0\\\\x^4+16x^2-4x^2-64=0\\\\x^2(x^2-16)-4(x^2-16)=0\\\\(x^2-4)(x^2-16)=0\\\\x^2-4=0\ or\ x^2-16=0\\\\\text{ "Using }a^2-b^2=(a+b)(a-b)"\\\\x^2-4=x^2-2^2=(x-2)(x+2)\\\\x^2-16=x^2-4^2=(x+4)(x-4)

So, all the zeroes of the above equation will be

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7 0
3 years ago
Does 5x^2 + y =5 represent y as a function of x?
julia-pushkina [17]
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Are the following lines parallel y=3x-8 and y=3x+4
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