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Leto [7]
3 years ago
11

What is the slope of the line that passes through the points (-4, -1) and (-2, -5)

Mathematics
1 answer:
GrogVix [38]3 years ago
5 0
Slope: (y2-y1)/(x2-x1)
(-5-(-1))/(-2-(-4)) = -4/2 = -2
The slope is -2
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Label the parts of the triangle.<br> leg<br> leg<br> altitude<br> hypotenuse<br> right angle
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Answer: See Below

Step-by-step explanation:

One part we can label right off the bat is right angle. It is denoted with the red box. It forms a 90° angle, which is a right angle. At the very top pointing to the right angle, is right angle.

Altitude is another way of saying height. It is how tall the triangle is. The line that shows how tall the triangle is, is the line going down the triangle in the middle. That line is altitude.

Hypotenuse is the longest side of the triangle. It is also located directly across the right angle. Looking at the right angle, the bottom line is the hypotenuse.

Since we have 2 sides left, they are obviously the legs of the triangle.

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A term that has no variable factor is a what
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Step-by-step explanation:

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David has counters. Lisa has 5 more counters than David. Samia has 4 times as many counters as David. The total number of counte
s2008m [1.1K]

Answer:

if 'c' equals number of counters, the answer is 6c + 5

Step-by-step explanation:

david has 'c'

lisa has '5+c'

samia has '4c'

add all terms together:  c + 5 + c + 4c = 6c + 5

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Step-by-step explanation:

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What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
4 years ago
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