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nirvana33 [79]
3 years ago
11

How can I find equivalent expressions to the given expression?

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer:

\frac{36t^2}{6^t} ~~ Not ~Equivalent

\frac{6t^2}{36^t} ~ ~Equivalent   ✔︎

6^{t^2} *36^t ~~ Not~ Equivalent

᪥༄᪥༄᪥༄᪥༄᪥༄᪥༄

Hope it helps...

Have a great day!!.

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2025bellikar avatar
Novosadov [1.4K]

Answer:

sweet

Step-by-step explanation:

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3 0
2 years ago
2x+3y=12 complete the missing value in the solution to the equation
likoan [24]

Answer:

(-6,8) is your answer.

Step-by-step explanation:

1. 2x + 3y = 12

2. 2x +3 * 8 = 12

3. 2x + 24 = 12

4. 2x = -12

5. x = -6

So, our final answer is (-6,8)

6 0
3 years ago
Prove that the shape below is a rectangle.
Ulleksa [173]

Answer:

HG = EF

GF = HE

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
If ax+3=7-bx what is x expressed in terms of a and b
Mekhanik [1.2K]
All we want to do is get an equation with just x on one side and no x's on the other.
We can use inverse operations to accomplish this.

First, bring bx to the left side. Subtract the 3.
Factor ax+bx to x(a+b). (this is pretty much reversing the distributive property)
Divide by a+b and you are left with just x on the left side as 4/(a+b).

ax+3=7-bx \\ ax+bx+3=7-bx+bx\\ax+bx+3=7 \\\\ ax+bx+3-3=7-3\\ax+bx=4 \\\\ x(a+b)=4 \\\frac{x(a+b)}{a+b}=\frac{4}{a+b}\\\boxed{x=\frac{4}{a+b}}
7 0
3 years ago
The population of town increases by5℅ every year. In the last year, the population was 80,000. 1) find the present population 2)
Readme [11.4K]

Answer:

last year it was 80k

Step-by-step explanation:

Population increases by 5% every year

Last year it was 80,000

PRESENT POPULATION

Present population = 80,000 + 5% off 80,000

                               = 80,000 + 5/100 × 80,000

                               = 80,000 + 5 × 800

                               = 80,000 + 4,000

                               = 84,000

AFTER ONE YEAR

After this , the population again increases by 5%

Population = 84,000 + 5% off 84,000

                 = 84,000 + 5/100 × 84,000

                 = 84,000 + 5 × 840

                 = 84,000 + 4,200

                 = 88,200

ANSWERS

The population of present year is 84,000

After one year , the population becomes 88,200

Hope it helps :-)

5 0
2 years ago
Read 2 more answers
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