Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
Answer:
g(x) - f(x) = -14x - 3
Step-by-step explanation:
We need to subtract the function f(x) = 9x + 4 from the function g(x) = -5 + 1. Rewriting these two functions in columns, we get
g(x)= -5x+1
- f(x) = -(9x+4) Note: Use parentheses as shown here.
--------------------
g(x) - f(x) = -14x - 3
STR and QTP are both equal 180
so PTS +PTR=180 andQTR+PTR=180 which means
PTS=QTR(for a shorter explanation they are staying against each other in a line cross
11y-110=4y-5
7y=105
y=105:7
y=15 grafe which means
PTS
y*4-5=55 grade
3.3 is greater than 3.01
Hope this helps!
Answer:
non-linear
Step-by-step explanation:
