Answer:2/1
Step-by-step explanation:
You just flip the fraction
Answer:
nah ion add bots, look at my yt channel
bumpy9
Step-by-step explanation:
again, bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
![\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-2)}{6-3}\implies \cfrac{2+2}{6-3}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=\cfrac{4}{3}(x-3)\implies y+2=\cfrac{4}{3}x-4 \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B3%7D~%2C~%5Cstackrel%7By_1%7D%7B-2%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B6%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B2-%28-2%29%7D%7B6-3%7D%5Cimplies%20%5Ccfrac%7B2%2B2%7D%7B6-3%7D%5Cimplies%20%5Ccfrac%7B4%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%28-2%29%3D%5Ccfrac%7B4%7D%7B3%7D%28x-3%29%5Cimplies%20y%2B2%3D%5Ccfrac%7B4%7D%7B3%7Dx-4%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
LnA +LnB= LnA.B
so we get <span>Log3(X-5)+log3(x+3)=Ln3(x-5)(x+3)=2 implies
</span>(x-5)(x+3)=2^3=8, so we can solve easily the quadratic equation
x^2-2x-23=0, there are two solution x=1 -sqrt(24), and x=1+sqrt(24)
Answer:
x=1
Step-by-step explanation:
X= means that it is the vertical line on that number, so x=1 would be the vertical lines going through 1, which would be in the middle of the parabola, thus having symmetry
