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allochka39001 [22]
3 years ago
12

Solve the inequality for y.

Mathematics
2 answers:
Pepsi [2]3 years ago
4 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:

y≥9

Interval Notation:

(9,∞)

hope this helps

dsp733 years ago
3 0

63 <= 7y

To solve for y just divide both sides by 7:

Y <= 63/7

Y <= 9

Because 63 is less than , you need to reverse the inequality sign.

The answer becomes y >=9

Now when you replace y with a number from 9 or higher the inequality will be true.

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40-20 a new smaller triangle is formed

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Is the first one correct and what are the ages? Thanks
Fantom [35]

Answer:

a = 30°

Step-by-step explanation:

We need to find the value of a.

We know that, a straight line makes an angle of 180°.

In this case,

a+3a+2a = 180

6a = 180

a = 30°

So, the value of a is equal to 30°.

8 0
3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
Brenda can deliver 644 newspapers in 7 hour how many newspapers can brenda deliver in 9 hours
Naya [18.7K]
In 7 hours 644 newpapers 
in one hour it is 644/7= 92
in 9 hours-> 92x9 =828 newspapers
6 0
3 years ago
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